假设我有一个网址

我有一个用户输入的查询，例如：

random word ￡500 bank $

我希望结果是正确编码的URL:

实现这一目标的最佳方法是什么？我尝试了URLEncoder并创建了uri/url对象，但没有一个是正确的。

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(P)字母名称0应该是去。You only need to keep in mind to encide only the individual query string parameter name and/or value，not the entire URL，for sure not the query string parameter separator character EDOCX1 individual 1.Nor the parameter name-value separator character EDOCX1.(p)字母名称(P)Note that spaces in query parameters are represented by EDOCX1 commercial 3，not EDOCX1 commercial 4，which is legitimately valid.The EDOCX1 4 universal is usually to be used to represent spaces in uri itself(the part before the uri-query string separator character EDOCX1 individual 6)，not in query string(the part after EDOCX1 individual 6).(p)(P)还注意到有两种不同的英文方法。One without charset argument and another with.一个没有标记的争论是忧郁的。从未使用过这一方法，也从未使用过这一方法。The Javado even explicitly recommends to use the UTF-8 encourage，as mandated by RfC3986 and W3C.(p)布尔奇1See also：

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(P)我不会用字母名称0Besides being impully named(EDOCX1 simplication 0)has nothing to do with URLS)，ineficient(it used a EDOCX1 indicated of builder and does a couple of other things that are slow)its also way too easy to screw it up.(p)(P)Instead I would use EDOCX1 pental 12 common or spring's EDOCX1 penal 13 or commons apache EDOCX1.The reason being you have to escape the query parameter s name(ie Balusc's answer EDOCX1 original 15)differently than the parameter value.(p)(P)The only down to the above(that I found out painfully)i s that URL's not a true subset of uri's.(p)(P)Sample Code：(p)字母名称(P)因为我只是把它与其他的答案联系起来，这是一个社区维基。Feel free to edit.(p)

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(P)你需要先创造一个像你这样的人(p)字母名称(P)他们把Uri变成了Ascii String：(p)字母名称(P)Now your URL string is completely encued first we did simple URL encoming and then we turned it to ASCI string to make sure no character outside US-ASCI are remaining in string.这真是太棒了(p)

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(P)Guava 15 has now added a set of straightforward URL escapers.(p)

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(P)Apache http://components library provides a neat option for building and encourage query params-(p)(P)With httpcomponents 4.x use-乌兰(p)(P)For httpclient 3.x use-缩小(p)

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(P)在这里，你可以使用一种方法在你的法典中转换一个URL String and Map of Parameters to a valid encoed URL string containing the query parameters.(p)字母名称

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(P)Use the following standard Java solution(passes around 100 of the testcases provided by web platform tests)：(p)(P)0.如果URL是永久缩小。Replace'+'enceded spaces with'%20'enceded spaces.(p)(P)1.将URL转化为结构党。使用EDOCX1为它。(p)(P)2.Each Structural Part Properly！(p)(P)3.使用EDOCX1 19字体到上帝的名字。(p)(P)4.使用EDOCX1 20发音到Percent-Encode，NFC enceded Unicode(Better Would be NFCC！)For more info see:how to encode properly this URL(p)字母名称(P)Prints(p)字母名称(P)这里有些例子表明，这也将是一项工作。(p)字母名称

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(P)In my case I just need to pass the whole URL and encode only the value of each parameters.I did't find a common code to do that so…！So I created this small method to do the job：(p)字母名称(P)IT uses org.apache.commons.lang3.stringutils(p)

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(P)In Android I would use this code:(p)字母名称(P)伊多克X1字体16是伊多克X1字体17(p)

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Use this:Urlencoder.encode(query，standard charsets.utf---U8.displayename()；Or this:Urlencoder.encode(query，"UTF-8")；

(P)你可以使用民间法典。(p)字母名称

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