关于python：从数组中删除所有特定值


Remove all specific value from array

我必须从数组中删除所有特定的值(如果有的话)，所以我写：

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while value_to_remove in my_array:
    my_array.remove(value_to_remove)

通过一个命令，是否有更多的Python方法来完成这个任务？

您可以尝试：

filter (lambda a: a != value_to_remove, my_array)。

例子：

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>>> my_array = ["abc","def","xyz","abc","pop","abc"]
>>> filter (lambda a: a !="abc", my_array)
['def', 'xyz', 'pop']
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clean_array = [element for element in my_array if value_to_remove != element]

my_array = ('a','b','a','c')
value_to_remove = 'a'
>>> clean_array = [element for element in my_array if value_to_remove != element]
>>> clean_array
['b', 'c']

号

使用itertools.ifilter：

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import itertools

my_array = list(itertools.ifilter(lambda x: x != value_to_remove, my_array))
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不要错过有一个非常有效的方法，如下所示：

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import numpy as Numpy

a = Numpy.array([1,7,3,4,4,6,3,8,7,0,8])
b = Numpy.array(['1','7','3','4','4','6','3','8','7','0','8'])
c = Numpy.array([0.1,9.8,-0.4,0.0,9.8,13.7])
d = Numpy.array(['one','three','five','four','three'])

print a
print a[a!=3]

print b
print b[b!='3']

print c
print c[c!=9.8]

print d
print d[d!='three']

。

你会得到：

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>>>
[1 7 3 4 4 6 3 8 7 0 8]
[1 7 4 4 6 8 7 0 8]
['1' '7' '3' '4' '4' '6' '3' '8' '7' '0' '8']
['1' '7' '4' '4' '6' '8' '7' '0' '8']
[  0.1   9.8  -0.4   0.    9.8  13.7]
[  0.1  -0.4   0.   13.7]
['one' 'three' 'five' 'four' 'three']
['one' 'five' 'four']