关于iphone：NSInvalidArgumentException，原因：’JSON写入中的类型无效（__NSDate）’


NSInvalidArgumentException, reason: 'Invalid type in JSON write (__NSDate)'

当我尝试对nsdate对象进行json编码时，我得到了这个异常，我相信nsdate与json编码不兼容。但我必须对日期进行编码。有什么解决办法吗？

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*** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: 'Invalid type in JSON write (__NSDate)'

你在商店nsstring第一日期。然后你nsdate to convert字符串。P＞＜／

我知道你可以参考：P＞＜／

nsstring(与to nsdate转换回来)P＞＜／

nsstring to nsdate转换问题P＞＜／

nsstring nsdate how to convert to using nsdateformatter？P＞＜／

相关讨论

nsdate convert to nsstring尽量和编码。P＞＜／

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- (NSString *) changeDateToDateString :(NSDate *) date {

    NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
    [dateFormatter setTimeZone:[NSTimeZone localTimeZone]];
    NSLocale *locale = [NSLocale currentLocale];
    NSString *dateFormat = [NSDateFormatter dateFormatFromTemplate:@"hh mm" options:0 locale:locale];
    [dateFormatter setDateFormat:dateFormat];
    [dateFormatter setLocale:locale];
    NSString *dateString = [dateFormatter stringFromDate:date];
    return dateString;
}

你必须为你的第一noted，nsdate nsstring convert to an。它不是立即清楚，不管一个人多，which should be the公社中的日期格式。回答：the can be found here"how does not specify JSON本身通过JavaScript公社should be，but does"——iso8601。P＞＜／

here is an iso8601 from a method for helper类转换nsdate，埃里卡丧盾：礼貌P＞＜／

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- (NSString *)ISO8601 {
    struct tm time;
    time_t interval = [self timeIntervalSince1970];
    gmtime_r(&interval, &time);
    char *x = calloc(1, 21);
    strftime_l(x, 20,"%FT%TZ", &time, gmtlocale);
    NSString *string = [NSString stringWithUTF8String:x];
    free(x);
    return string;
}

如果你得到一iso8601 JSON字符串和后台在payload convert it to an想nsdate method for this class，使用nsdate：P＞＜／

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+ (NSDate *)dateFromISO8601:(NSString *)string {
    if(!string) return nil;
    if (![string isKindOfClass:[NSString class]]) return nil;
    struct tm time;
    strptime_l([string UTF8String],"%FT%TZ", &time, gmtlocale);
    return [NSDate dateWithTimeIntervalSince1970:timegm(&time)];
}

你有想？P＞＜／

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updateDate = [NSNumber numberWithFloat:[[NSDate date] timeIntervalSince1970]];

在这里描述的程序办理：not as nsdate SDK的支持对象P＞＜／

跟随这些步：P＞＜／

1。转换日期格式：JSON theP＞＜／

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 NSDateFormatter *formatter = [[[NSDateFormatter alloc] init]autorelease];
 [formatter setDateFormat:@"Z"];
 NSString *updateDate = [NSString stringWithFormat:@"/Date(%.0f000%@)/", [[NSDate date] timeIntervalSince1970],[formatter stringFromDate:[NSDate date]]];

2。在与后embed some阵列数组的。P＞＜／

相关讨论

the Way to store和扩retrieve JSON对象在nsdate摇篮使用timeintervalsince1970 to the property of nsdate。P＞＜／

nstimeinterval is the returned(双)可以转换easily好漂亮的标准和对象：在nsdate back to usingP＞＜／

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NSDate dateWithTimeIntervalSince1970:<#(NSTimeInterval)#>

为我们的家园，我们是用JSON对象to convert to an地幔和我们的目标nsdate with one of its is missing jsontransformer物业P＞＜／

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@property (nonatomic) NSDate *expiryDate;

where：P＞＜／

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+ (NSValueTransformer *)expiryDateJSONTransformer {
     return [MTLValueTransformer transformerUsingForwardBlock:^id(NSString *dateString, BOOL *success, NSError *__autoreleasing *error) {
        return [self.dateFormatter dateFromString:dateString];
    } reverseBlock:^id(NSDate *date, BOOL *success, NSError *__autoreleasing *error) {
        return [self.dateFormatter stringFromDate:date];
    }];
}

+ (NSDateFormatter *)dateFormatter {
    NSDateFormatter *df = [NSDateFormatter new];
    df.dateFormat = @"yyyy-MM-dd";
    return df;
}

You must convert to the日期字符串之前你试图编码它。there are examples到处知道它足够容易should be to findP＞＜／