关于python：如何计算两个给定日期之间的天数？

How to calculate number of days between two given dates?

如果我有两个日期(例如，EDOCX1&0)和EDOCX1&1)，那么在这两个日期之间，什么是最好的日子数？

如果有两个日期对象，只需减去它们即可。

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from datetime import date

d0 = date(2008, 8, 18)
d1 = date(2008, 9, 26)
delta = d1 - d0
print delta.days

文件的相关部分：https://docs.python.org/library/datetime.html。

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使用日期时间的力量：

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from datetime import datetime
date_format ="%m/%d/%Y"
a = datetime.strptime('8/18/2008', date_format)
b = datetime.strptime('9/26/2008', date_format)
delta = b - a
print delta.days # that's it

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圣诞节前几天：

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>>> import datetime
>>> today = datetime.date.today()
>>> someday = datetime.date(2008, 12, 25)
>>> diff = someday - today
>>> diff.days
86

这里有更多的算术。

您需要datetime模块。

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>>> from datetime import datetime, timedelta
>>> datetime(2008,08,18) - datetime(2008,09,26)
datetime.timedelta(4)

或其他示例：

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Python 2.5.2 (r252:60911, Feb 22 2008, 07:57:53)
[GCC 4.0.1 (Apple Computer, Inc. build 5363)] on darwin
Type"help","copyright","credits" or"license" for more information.
>>> import datetime
>>> today = datetime.date.today()
>>> print today
2008-09-01
>>> last_year = datetime.date(2007, 9, 1)
>>> print today - last_year
366 days, 0:00:00

正如这里指出的

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from datetime import datetime
start_date = datetime.strptime('8/18/2008',"%m/%d/%Y")
end_date = datetime.strptime('9/26/2008',"%m/%d/%Y")
print abs((end_date-start_date).days)

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它也可以很容易地与arrow一起完成：

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import arrow

a = arrow.get('2017-05-09')
b = arrow.get('2017-05-11')

delta = (b-a)
print delta.days

参考：http://arrow.readthedocs.io/en/latest/

不使用lib，只使用纯代码：

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#Calculate the Days between Two Date

daysOfMonths = [ 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]

def isLeapYear(year):

# Pseudo code for this algorithm is found at
# http://en.wikipedia.org/wiki/Leap_year#Algorithm
## if (year is not divisible by 4) then (it is a common Year)
#else if (year is not divisable by 100) then (ut us a leap year)
#else if (year is not disible by 400) then (it is a common year)
#else(it is aleap year)
return (year % 4 == 0 and year % 100 != 0) or year % 400 == 0

def Count_Days(year1, month1, day1):
if month1 ==2:
if isLeapYear(year1):
if day1 < daysOfMonths[month1-1]+1:
return year1, month1, day1+1
else:
if month1 ==12:
return year1+1,1,1
else:
return year1, month1 +1 , 1
else:
if day1 < daysOfMonths[month1-1]:
return year1, month1, day1+1
else:
if month1 ==12:
return year1+1,1,1
else:
return year1, month1 +1 , 1
else:
if day1 < daysOfMonths[month1-1]:
return year1, month1, day1+1
else:
if month1 ==12:
return year1+1,1,1
else:
return year1, month1 +1 , 1

def daysBetweenDates(y1, m1, d1, y2, m2, d2,end_day):

if y1 > y2:
m1,m2 = m2,m1
y1,y2 = y2,y1
d1,d2 = d2,d1
days=0
while(not(m1==m2 and y1==y2 and d1==d2)):
y1,m1,d1 = Count_Days(y1,m1,d1)
days+=1
if end_day:
days+=1
return days

# Test Case

def test():
test_cases = [((2012,1,1,2012,2,28,False), 58),
((2012,1,1,2012,3,1,False), 60),
((2011,6,30,2012,6,30,False), 366),
((2011,1,1,2012,8,8,False), 585 ),
((1994,5,15,2019,8,31,False), 9239),
((1999,3,24,2018,2,4,False), 6892),
((1999,6,24,2018,8,4,False),6981),
((1995,5,24,2018,12,15,False),8606),
((1994,8,24,2019,12,15,True),9245),
((2019,12,15,1994,8,24,True),9245),
((2019,5,15,1994,10,24,True),8970),
((1994,11,24,2019,8,15,True),9031)]

for (args, answer) in test_cases:
result = daysBetweenDates(*args)
if result != answer:
print"Test with data:", args,"failed"
else:
print"Test case passed!"

test()

对于计算日期和时间，有几个选项，但我会用简单的方法：

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import datetime
import dateutil.relativedelta

# current time
date_and_time = datetime.datetime.now()
date_only = date.today()
time_only = datetime.datetime.now().time()

# calculate date and time
result = date_and_time - datetime.timedelta(hours=26, minutes=25, seconds=10)

# calculate dates: years (-/+)
result = date_only - dateutil.relativedelta.relativedelta(years=10)

# months
result = date_only - dateutil.relativedelta.relativedelta(months=10)

# days
result = date_only - dateutil.relativedelta.relativedelta(days=10)

# calculate time
result = date_and_time - datetime.timedelta(hours=26, minutes=25, seconds=10)
result.time()

希望它有帮助

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from datetime import date
def d(s):
[month, day, year] = map(int, s.split('/'))
return date(year, month, day)
def days(start, end):
return (d(end) - d(start)).days
print days('8/18/2008', '9/26/2008')

当然，这假定您已经验证了日期的格式为r'\d+/\d+/\d+'。

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以下是解决此问题的三种方法：

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from datetime import datetime

Now = datetime.now()
StartDate = datetime.strptime(str(Now.year) +'-01-01', '%Y-%m-%d')
NumberOfDays = (Now - StartDate)

print(NumberOfDays.days) # Starts at 0
print(datetime.now().timetuple().tm_yday) # Starts at 1
print(Now.strftime('%j')) # Starts at 1