Named string formatting in C#
是否有任何方法可以按名称而不是C中的位置来格式化字符串?
在Python中,我可以这样做(无耻地从这里被盗):
1 2 3 | >>> print '%(language)s has %(#)03d quote types.' % \ {'language':"Python","#": 2} Python has 002 quote types. |
用C语言有什么方法可以做到这一点吗?比如说:
1 | String.Format("{some_variable}: {some_other_variable}", ...); |
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使用变量名这样做是很好的,但是字典也是可以接受的。
没有处理此问题的内置方法。
这里有一个方法
1 | string myString ="{foo} is {bar} and {yadi} is {yada}".Inject(o); |
。
这是另一个
1 | Status.Text ="{UserName} last logged in at {LastLoginDate}".FormatWith(user); |
。
第三种改进方法,部分基于上述两种方法,来自Phil Haack。
我刚在博客上发布了一个实现:http://haacked.com/archive/2009/01/04/fun-with-named-formats-string-analysis-and-edge-cases.aspx
它解决了这些其他实现在使用大括号转义时遇到的一些问题。这篇文章有细节。它可以做数据绑定器,也可以进行评估,但是仍然很快。
在C 6.0和Visual Basic 14中添加了内插字符串。
两者都是通过新的Roslyn编译器在Visual Studio 2015中引入的。
C 6.0:
return"\{someVariable} and also \{someOtherVariable}" 或江户十一〔一〕号资料来源:C 6.0的新功能
nbsp;
VB 14:
江户十一〔一〕号
- 资料来源:vb 14的新功能
值得注意的功能(在Visual Studio 2015 IDE中):
- 支持语法着色-突出显示字符串中包含的变量
- 支持重构-重命名时,字符串中包含的变量也将被重命名
- 实际上,不仅支持变量名,而且支持表达式-例如,不仅
{index} 有效,而且{(index + 1).ToString().Trim()} 也有效。
享受吧!(在vs中单击"发送微笑")。
您还可以使用类似以下匿名类型:
1 2 3 4 5 6 7 | public string Format(string input, object p) { foreach (PropertyDescriptor prop in TypeDescriptor.GetProperties(p)) input = input.Replace("{" + prop.Name +"}", (prop.GetValue(p) ??"(null)").ToString()); return input; } |
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当然,如果您还想解析格式,就需要更多的代码,但是您可以使用如下函数格式化字符串:
1 |
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似乎没有现成的方法可以做到这一点。不过,实现您自己的
1 2 3 4 5 6 7 8 |
输出:
1 | Python has 2 quote types |
。
警告是不能混合使用
框架本身并没有提供这样做的方法,但是您可以看看ScottHanselman的文章。示例用法:
1 2 3 | Person p = new Person(); string foo = p.ToString("{Money:C} {LastName}, {ScottName} {BirthDate}"); Assert.AreEqual("$3.43 Hanselman, {ScottName} 1/22/1974 12:00:00 AM", foo); |
这段由詹姆斯·牛顿·金编写的代码是相似的,并且与子属性和索引一起工作。
1 | string foo ="Top result for {Name} was {Results[0].Name}".FormatWith(student)); |
。
james的代码依赖于system.web.ui.databinder来解析字符串,并且需要引用system.web,有些人不喜欢在非web应用程序中这样做。
编辑:哦,如果你没有一个对象的属性准备好了,它们可以很好地处理匿名类型:
1 2 3 | string name = ...; DateTime date = ...; string foo ="{Name} - {Birthday}".FormatWith(new { Name = name, Birthday = date }); |
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请参阅https://stackoverflow.com/questions/271398?页码=2
通过"链接到扩展名",您可以编写以下内容:
1 |
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你就可以得到
我认为最接近的是索引格式:
1 | String.Format("{0} has {1} quote types.","C#","1"); |
还有string.replace(),如果您愿意多步骤执行,并相信在字符串中的任何其他地方都找不到您的"变量",请执行以下操作:
1 2 | string MyString ="{language} has {n} quote types."; MyString = MyString.Replace("{language}","C#").Replace("{n}","1"); |
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展开此项以使用列表:
1 2 3 4 5 | List<KeyValuePair<string, string>> replacements = GetFormatDictionary(); foreach (KeyValuePair<string, string> item in replacements) { MyString = MyString.Replace(item.Key, item.Value); } |
您也可以使用字典
1 | replacements.ForEach(delegate(KeyValuePair<string,string>) item) { MyString = MyString.Replace(item.Key, item.Value);}); |
。
lambda会更简单,但我仍然使用.NET 2.0。还要注意,.replace()的性能在迭代使用时并不出色,因为.NET中的字符串是不可变的。此外,这要求
我的开源库regextra支持命名格式(除其他外)。它目前以.NET 4.0+为目标,可在Nuget上使用。我也有一篇关于它的介绍性博客文章:RegExtra:帮助你减少(问题)2。
命名格式位支持:
- 基本格式
- 嵌套属性格式
- 字典格式
- 分隔符的转义
- 标准/自定义/IFormatProvider字符串格式
例子:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 | var order = new { Description ="Widget", OrderDate = DateTime.Now, Details = new { UnitPrice = 1500 } }; string template ="We just shipped your order of '{Description}', placed on {OrderDate:d}. Your {{credit}} card will be billed {Details.UnitPrice:C}."; string result = Template.Format(template, order); // or use the extension: template.FormatTemplate(order); |
结果:
We just shipped your order of 'Widget', placed on 2/28/2014. Your {credit} card will be billed $1,500.00.
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查看项目的github链接(上面)和wiki以获取其他示例。
检查这个:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 | public static string StringFormat(string format, object source) { var matches = Regex.Matches(format, @"\{(.+?)\}"); List<string> keys = (from Match matche in matches select matche.Groups[1].Value).ToList(); return keys.Aggregate( format, (current, key) => { int colonIndex = key.IndexOf(':'); return current.Replace( "{" + key +"}", colonIndex > 0 ? DataBinder.Eval(source, key.Substring(0, colonIndex),"{0:" + key.Substring(colonIndex + 1) +"}") : DataBinder.Eval(source, key).ToString()); }); } |
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样品:
1 2 3 | string format ="{foo} is a {bar} is a {baz} is a {qux:#.#} is a really big {fizzle}"; var o = new { foo = 123, bar = true, baz ="this is a test", qux = 123.45, fizzle = DateTime.Now }; Console.WriteLine(StringFormat(format, o)); |
与其他解决方案相比,性能相当不错。
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 | private static Regex s_NamedFormatRegex = new Regex(@"\{(?!\{)(?<key>[\w]+)(:(?<fmt>(\{\{|\}\}|[^\{\}])*)?)?\}", RegexOptions.Compiled); public static StringBuilder AppendNamedFormat(this StringBuilder builder,IFormatProvider provider, string format, IDictionary<string, object> args) { if (builder == null) throw new ArgumentNullException("builder"); var str = s_NamedFormatRegex.Replace(format, (mt) => { string key = mt.Groups["key"].Value; string fmt = mt.Groups["fmt"].Value; object value = null; if (args.TryGetValue(key,out value)) { return string.Format(provider,"{0:" + fmt +"}", value); } else { return mt.Value; } }); builder.Append(str); return builder; } public static StringBuilder AppendNamedFormat(this StringBuilder builder, string format, IDictionary<string, object> args) { if (builder == null) throw new ArgumentNullException("builder"); return builder.AppendNamedFormat(null, format, args); } |
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例子:
1 2 3 4 5 6 7 8 9 |
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输出:你好,Wayjet,今天是2011-05-04,这是你第18次登录,积分100.40
以下是任何对象的简单方法:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 | using System.Text.RegularExpressions; using System.ComponentModel; public static string StringWithFormat(string format, object args) { Regex r = new Regex(@"\{([A-Za-z0-9_]+)\}"); MatchCollection m = r.Matches(format); var properties = TypeDescriptor.GetProperties(args); foreach (Match item in m) { try { string propertyName = item.Groups[1].Value; format = format.Replace(item.Value, properties[propertyName].GetValue(args).ToString()); } catch { throw new FormatException("The format string is not valid"); } } return format; } |
。
下面介绍如何使用它:
1 2 | DateTime date = DateTime.Now; string dateString = StringWithFormat("{Month}/{Day}/{Year}", date); |
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产量:2012年2月27日
我怀疑这是可能的。首先想到的是如何访问局部变量名?
然而,使用LINQ和lambda表达式来实现这一点可能有一些聪明的方法。
这是我以前做的。它使用一个采用单个参数的格式方法扩展字符串。好的是它将使用标准字符串.format,如果您提供一个像int这样的简单参数,但是如果您使用类似匿名类型的参数,它也会起作用。
示例用法:
1 |
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会导致"史密斯家有4个孩子"。
它不会做疯狂的绑定工作,比如数组和索引器。但它是超简单和高性能的。
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 153 154 155 156 157 158 159 160 161 162 163 164 165 166 167 168 169 170 171 172 173 174 175 176 177 178 179 180 181 182 183 184 185 186 187 188 189 190 191 192 193 194 195 196 197 198 199 200 201 202 203 204 205 206 207 208 209 210 211 212 213 214 215 216 217 218 219 | public static class AdvancedFormatString { /// <summary> /// An advanced version of string.Format. If you pass a primitive object (string, int, etc), it acts like the regular string.Format. If you pass an anonmymous type, you can name the paramters by property name. /// </summary> /// <param name="formatString"></param> /// <param name="arg"></param> /// <returns></returns> /// <example> ///"The {Name} family has {Children} children".Format(new { Children = 4, Name ="Smith" }) /// /// results in ///"This Smith family has 4 children /// </example> public static string Format(this string formatString, object arg, IFormatProvider format = null) { if (arg == null) return formatString; var type = arg.GetType(); if (Type.GetTypeCode(type) != TypeCode.Object || type.IsPrimitive) return string.Format(format, formatString, arg); var properties = TypeDescriptor.GetProperties(arg); return formatString.Format((property) => { var value = properties[property].GetValue(arg); return Convert.ToString(value, format); }); } public static string Format(this string formatString, Func<string, string> formatFragmentHandler) { if (string.IsNullOrEmpty(formatString)) return formatString; Fragment[] fragments = GetParsedFragments(formatString); if (fragments == null || fragments.Length == 0) return formatString; return string.Join(string.Empty, fragments.Select(fragment => { if (fragment.Type == FragmentType.Literal) return fragment.Value; else return formatFragmentHandler(fragment.Value); }).ToArray()); } private static Fragment[] GetParsedFragments(string formatString) { Fragment[] fragments; if ( parsedStrings.TryGetValue(formatString, out fragments) ) { return fragments; } lock (parsedStringsLock) { if ( !parsedStrings.TryGetValue(formatString, out fragments) ) { fragments = Parse(formatString); parsedStrings.Add(formatString, fragments); } } return fragments; } private static Object parsedStringsLock = new Object(); private static Dictionary<string,Fragment[]> parsedStrings = new Dictionary<string,Fragment[]>(StringComparer.Ordinal); const char OpeningDelimiter = '{'; const char ClosingDelimiter = '}'; /// <summary> /// Parses the given format string into a list of fragments. /// </summary> /// <param name="format"></param> /// <returns></returns> static Fragment[] Parse(string format) { int lastCharIndex = format.Length - 1; int currFragEndIndex; Fragment currFrag = ParseFragment(format, 0, out currFragEndIndex); if (currFragEndIndex == lastCharIndex) { return new Fragment[] { currFrag }; } List<Fragment> fragments = new List<Fragment>(); while (true) { fragments.Add(currFrag); if (currFragEndIndex == lastCharIndex) { break; } currFrag = ParseFragment(format, currFragEndIndex + 1, out currFragEndIndex); } return fragments.ToArray(); } /// <summary> /// Finds the next delimiter from the starting index. /// </summary> static Fragment ParseFragment(string format, int startIndex, out int fragmentEndIndex) { bool foundEscapedDelimiter = false; FragmentType type = FragmentType.Literal; int numChars = format.Length; for (int i = startIndex; i < numChars; i++) { char currChar = format[i]; bool isOpenBrace = currChar == OpeningDelimiter; bool isCloseBrace = isOpenBrace ? false : currChar == ClosingDelimiter; if (!isOpenBrace && !isCloseBrace) { continue; } else if (i < (numChars - 1) && format[i + 1] == currChar) {//{{ or }} i++; foundEscapedDelimiter = true; } else if (isOpenBrace) { if (i == startIndex) { type = FragmentType.FormatItem; } else { if (type == FragmentType.FormatItem) throw new FormatException("Two consequtive unescaped { format item openers were found. Either close the first or escape any literals with another {."); //curr character is the opening of a new format item. so we close this literal out string literal = format.Substring(startIndex, i - startIndex); if (foundEscapedDelimiter) literal = ReplaceEscapes(literal); fragmentEndIndex = i - 1; return new Fragment(FragmentType.Literal, literal); } } else {//close bracket if (i == startIndex || type == FragmentType.Literal) throw new FormatException("A } closing brace existed without an opening { brace."); string formatItem = format.Substring(startIndex + 1, i - startIndex - 1); if (foundEscapedDelimiter) formatItem = ReplaceEscapes(formatItem);//a format item with a { or } in its name is crazy but it could be done fragmentEndIndex = i; return new Fragment(FragmentType.FormatItem, formatItem); } } if (type == FragmentType.FormatItem) throw new FormatException("A format item was opened with { but was never closed."); fragmentEndIndex = numChars - 1; string literalValue = format.Substring(startIndex); if (foundEscapedDelimiter) literalValue = ReplaceEscapes(literalValue); return new Fragment(FragmentType.Literal, literalValue); } /// <summary> /// Replaces escaped brackets, turning '{{' and '}}' into '{' and '}', respectively. /// </summary> /// <param name="value"></param> /// <returns></returns> static string ReplaceEscapes(string value) { return value.Replace("{{","{").Replace("}}","}"); } private enum FragmentType { Literal, FormatItem } private class Fragment { public Fragment(FragmentType type, string value) { Type = type; Value = value; } public FragmentType Type { get; private set; } /// <summary> /// The literal value, or the name of the fragment, depending on fragment type. /// </summary> public string Value { get; private set; } } } |
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尽管公认的答案给出了一些很好的例子,但是.inject和一些haack示例并不处理转义。许多人还严重依赖于regex(较慢)或databinder.eval,它在.NET核心和其他一些环境中不可用。
考虑到这一点,我已经编写了一个简单的基于状态机的解析器,它可以通过字符进行流式处理,并逐个字符地写入
当输入包含不平衡的大括号和/或其他错误时,它处理
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 153 154 155 156 157 158 159 160 161 162 163 164 165 166 167 168 | public static class StringExtension { /// <summary> /// Extension method that replaces keys in a string with the values of matching object properties. /// </summary> /// <param name="formatString">The format string, containing keys like {foo} and {foo:SomeFormat}.</param> /// <param name="injectionObject">The object whose properties should be injected in the string</param> /// <returns>A version of the formatString string with keys replaced by (formatted) key values.</returns> public static string FormatWith(this string formatString, object injectionObject) { return formatString.FormatWith(GetPropertiesDictionary(injectionObject)); } /// <summary> /// Extension method that replaces keys in a string with the values of matching dictionary entries. /// </summary> /// <param name="formatString">The format string, containing keys like {foo} and {foo:SomeFormat}.</param> /// <param name="dictionary">An <see cref="IDictionary"/> with keys and values to inject into the string</param> /// <returns>A version of the formatString string with dictionary keys replaced by (formatted) key values.</returns> public static string FormatWith(this string formatString, IDictionary<string, object> dictionary) { char openBraceChar = '{'; char closeBraceChar = '}'; return FormatWith(formatString, dictionary, openBraceChar, closeBraceChar); } /// <summary> /// Extension method that replaces keys in a string with the values of matching dictionary entries. /// </summary> /// <param name="formatString">The format string, containing keys like {foo} and {foo:SomeFormat}.</param> /// <param name="dictionary">An <see cref="IDictionary"/> with keys and values to inject into the string</param> /// <returns>A version of the formatString string with dictionary keys replaced by (formatted) key values.</returns> public static string FormatWith(this string formatString, IDictionary<string, object> dictionary, char openBraceChar, char closeBraceChar) { string result = formatString; if (dictionary == null || formatString == null) return result; // start the state machine! // ballpark output string as two times the length of the input string for performance (avoids reallocating the buffer as often). StringBuilder outputString = new StringBuilder(formatString.Length * 2); StringBuilder currentKey = new StringBuilder(); bool insideBraces = false; int index = 0; while (index < formatString.Length) { if (!insideBraces) { // currently not inside a pair of braces in the format string if (formatString[index] == openBraceChar) { // check if the brace is escaped if (index < formatString.Length - 1 && formatString[index + 1] == openBraceChar) { // add a brace to the output string outputString.Append(openBraceChar); // skip over braces index += 2; continue; } else { // not an escaped brace, set state to inside brace insideBraces = true; index++; continue; } } else if (formatString[index] == closeBraceChar) { // handle case where closing brace is encountered outside braces if (index < formatString.Length - 1 && formatString[index + 1] == closeBraceChar) { // this is an escaped closing brace, this is okay // add a closing brace to the output string outputString.Append(closeBraceChar); // skip over braces index += 2; continue; } else { // this is an unescaped closing brace outside of braces. // throw a format exception throw new FormatException($"Unmatched closing brace at position {index}"); } } else { // the character has no special meaning, add it to the output string outputString.Append(formatString[index]); // move onto next character index++; continue; } } else { // currently inside a pair of braces in the format string // found an opening brace if (formatString[index] == openBraceChar) { // check if the brace is escaped if (index < formatString.Length - 1 && formatString[index + 1] == openBraceChar) { // there are escaped braces within the key // this is illegal, throw a format exception throw new FormatException($"Illegal escaped opening braces within a parameter - index: {index}"); } else { // not an escaped brace, we have an unexpected opening brace within a pair of braces throw new FormatException($"Unexpected opening brace inside a parameter - index: {index}"); } } else if (formatString[index] == closeBraceChar) { // handle case where closing brace is encountered inside braces // don't attempt to check for escaped braces here - always assume the first brace closes the braces // since we cannot have escaped braces within parameters. // set the state to be outside of any braces insideBraces = false; // jump over brace index++; // at this stage, a key is stored in current key that represents the text between the two braces // do a lookup on this key string key = currentKey.ToString(); // clear the stringbuilder for the key currentKey.Clear(); object outObject; if (!dictionary.TryGetValue(key, out outObject)) { // the key was not found as a possible replacement, throw exception throw new FormatException($"The parameter "{key}" was not present in the lookup dictionary"); } // we now have the replacement value, add the value to the output string outputString.Append(outObject); // jump to next state continue; } // if } else { // character has no special meaning, add it to the current key currentKey.Append(formatString[index]); // move onto next character index++; continue; } // else } // if inside brace } // while // after the loop, if all braces were balanced, we should be outside all braces // if we're not, the input string was misformatted. if (insideBraces) { throw new FormatException("The format string ended before the parameter was closed."); } return outputString.ToString(); } /// <summary> /// Creates a Dictionary from an objects properties, with the Key being the property's /// name and the Value being the properties value (of type object) /// </summary> /// <param name="properties">An object who's properties will be used</param> /// <returns>A <see cref="Dictionary"/> of property values </returns> private static Dictionary<string, object> GetPropertiesDictionary(object properties) { Dictionary<string, object> values = null; if (properties != null) { values = new Dictionary<string, object>(); PropertyDescriptorCollection props = TypeDescriptor.GetProperties(properties); foreach (PropertyDescriptor prop in props) { values.Add(prop.Name, prop.GetValue(properties)); } } return values; } } |
。
最终,所有的逻辑归结为10种主要状态——因为当状态机在一个括号外,同样在一个括号内时,下一个字符要么是左大括号,要么是转义左大括号,要么是右大括号,要么是转义右大括号,要么是普通字符。随着循环的进行,这些条件中的每一个都被单独处理,向输出
我实现了这个简单的类,它复制了string.format的功能(使用类时除外)。您可以使用字典或类型来定义字段。
https://github.com/sergueifederov/namedformatstring
C 6.0正在将此功能直接添加到语言规范中,因此
我用与现有解决方案稍有不同的方式解决了这个问题。它完成命名项替换的核心(而不是一些已经完成的反射位)。它非常快速和简单…这是我的解决方案:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 | /// <summary> /// Formats a string with named format items given a template dictionary of the items values to use. /// </summary> public class StringTemplateFormatter { private readonly IFormatProvider _formatProvider; /// <summary> /// Constructs the formatter with the specified <see cref="IFormatProvider"/>. /// This is defaulted to <see cref="CultureInfo.CurrentCulture">CultureInfo.CurrentCulture</see> if none is provided. /// </summary> /// <param name="formatProvider"></param> public StringTemplateFormatter(IFormatProvider formatProvider = null) { _formatProvider = formatProvider ?? CultureInfo.CurrentCulture; } /// <summary> /// Formats a string with named format items given a template dictionary of the items values to use. /// </summary> /// <param name="text">The text template</param> /// <param name="templateValues">The named values to use as replacements in the formatted string.</param> /// <returns>The resultant text string with the template values replaced.</returns> public string FormatTemplate(string text, Dictionary<string, object> templateValues) { var formattableString = text; var values = new List<object>(); foreach (KeyValuePair<string, object> value in templateValues) { var index = values.Count; formattableString = ReplaceFormattableItem(formattableString, value.Key, index); values.Add(value.Value); } return String.Format(_formatProvider, formattableString, values.ToArray()); } /// <summary> /// Convert named string template item to numbered string template item that can be accepted by <see cref="string.Format(string,object[])">String.Format</see> /// </summary> /// <param name="formattableString">The string containing the named format item</param> /// <param name="itemName">The name of the format item</param> /// <param name="index">The index to use for the item value</param> /// <returns>The formattable string with the named item substituted with the numbered format item.</returns> private static string ReplaceFormattableItem(string formattableString, string itemName, int index) { return formattableString .Replace("{" + itemName +"}","{" + index +"}") .Replace("{" + itemName +",","{" + index +",") .Replace("{" + itemName +":","{" + index +":"); } } |
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其使用方法如下:
1 2 3 4 5 6 7 8 9 10 11 12 | [Test] public void FormatTemplate_GivenANamedGuid_FormattedWithB_ShouldFormatCorrectly() { // Arrange var template ="My guid {MyGuid:B} is awesome!"; var templateValues = new Dictionary<string, object> { {"MyGuid", new Guid("{A4D2A7F1-421C-4A1D-9CB2-9C2E70B05E19}") } }; var sut = new StringTemplateFormatter(); // Act var result = sut.FormatTemplate(template, templateValues); //Assert Assert.That(result, Is.EqualTo("My guid {a4d2a7f1-421c-4a1d-9cb2-9c2e70b05e19} is awesome!")); } |
希望有人发现这有用!
1 2 3 | string language ="Python"; int numquotes = 2; string output = language +" has"+ numquotes +" language types."; |
编辑:我应该说的是,"不,我不相信你想做的是得到C的支持。这是你能得到的最接近的。"