关于java：Name和CanonicalName有什么区别？

What's the difference between Name and CanonicalName?

本问题已经有最佳答案，请猛点这里访问。

Java的EDOCX1 0和EDCOX1 1的区别是什么？

考虑以下程序：

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package org.test.stackoverflow;

public class CanonicalName {

public static void main(String[] args) {
CanonicalName cn = new CanonicalName();
cn.printClassNames();
}

private Anonymous anony;
private MyAnony myAnony;

public CanonicalName() {
anony = new Anonymous() {
public void printInterface() {
System.out.println("Anony Name:" + getClass().getName());
System.out.println("Anony CanonicalName:" + getClass().getCanonicalName());
}
};
myAnony = new MyAnony();
}

public void printClassNames() {
System.out.println("CanonicalName, Name:" + getClass().getName());
System.out.println("CanonicalName, CanonicalName:" + getClass().getCanonicalName());
anony.printInterface();
myAnony.printInterface();
}

private static interface Anonymous {
public void printInterface();
}

private static class MyAnony implements Anonymous {
public void printInterface() {
System.out.println("MyAnony Name:" + getClass().getName());
System.out.println("MyAnony CanonicalName:" + getClass().getCanonicalName());
}
}
}

输出：

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CanonicalName, Name: org.test.stackoverflow.CanonicalName
CanonicalName, CanonicalName: org.test.stackoverflow.CanonicalName
Anony Name: org.test.stackoverflow.CanonicalName$1
Anony CanonicalName: null
MyAnony Name: org.test.stackoverflow.CanonicalName$MyAnony
MyAnony CanonicalName: org.test.stackoverflow.CanonicalName.MyAnony

因此，对于基类，它们返回相同的东西。对于内部类，getName()使用$命名约定(即用于.class文件的内容)，getCanonicalName()返回在试图实例化类时将使用的内容。你不能用(一个小的)匿名类来实现这一点，所以getCanonicalName()返回空值。