关于python：如何获取Flask请求网址的不同部分？

How do I get the different parts of a Flask request's url?

我想检测请求是否来自localhost:5000或foo.herokuapp.com主机以及请求的路径。如何获得有关Flask请求的信息？

您可以通过几个Request字段检查url：

A user requests the following URL:

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http://www.example.com/myapplication/page.html?x=y

In this case the values of the above mentioned attributes would be the following:

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path /page.html
script_root /myapplication
base_url http://www.example.com/myapplication/page.html
url http://www.example.com/myapplication/page.html?x=y
url_root http://www.example.com/myapplication/

您可以通过适当的拆分轻松提取主体部分。

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另一个例子：

请求：

1	curl -XGET http://127.0.0.1:5000/alert/dingding/test?x=y

然后：

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request.method: GET
request.url: http://127.0.0.1:5000/alert/dingding/test?x=y
request.base_url: http://127.0.0.1:5000/alert/dingding/test
request.url_charset: utf-8
request.url_root: http://127.0.0.1:5000/
str(request.url_rule): /alert/dingding/test
request.host_url: http://127.0.0.1:5000/
request.host: 127.0.0.1:5000
request.script_root:
request.path: /alert/dingding/test
request.full_path: /alert/dingding/test?x=y

request.args: ImmutableMultiDict([('x', 'y')])
request.args.get('x'): y