check two dictionaries that have similar keys but different values
我有两本词典。dict1和dict2。dict 2的长度总是相同的，但dict1的长度不同。两部词典如下：
1 2 3 | dict2 = {"name":"martin","sex":"male","age":"97","address":"blablabla"} dict1 = {"name":"falak","sex":"female"} |
我想创建一个基于dict1和dict2的第三个字典。dict3将具有dict2的所有值。但所有那些在dict1中存在的键都将被替换。下面是结果dict3
1 | dict3 = {"name":"falak","sex":"female","age":"97","address":"blablabla"} |
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我可以用多个if语句来实现它，但是我希望有一种更聪明的方法。有人能指导我吗？
您是否尝试过：
1 | dict3 = dict(dict2, **dict1) |
或：
1 2 | dict3 = dict2.copy() dict3.update(dict1) |
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1 2 3 | import copy dict3 = copy.copy(dict2) dict3.update(dict1) |
首先，添加d1中具有d2中不存在的键的项。来自d1的所有其他键都在d2中。
然后，添加d2中的所有键，如果d1中没有这样的键，则从d2添加值；如果d1中存在键，则从d1添加值。
1 2 3 4 5 6 7 8 9 10 11 12 13 14 | dict2 = {"name":"martin","sex":"male","age":"97","address":"blablabla"} dict1 = {"name":"falak","sex":"female"} dic = dict() for key, val in dict1.items(): if key not in dict2.keys(): dic[key] = val for key, val in dict2.items(): if key not in dict1.keys(): dic[key] = val else: dic[key] = dict1[key] |
。
从python文档中：
update([other])
- Update the dictionary with the key/value pairs from other, overwriting existing keys.
- Returns None.
- update() accepts either another dictionary object or an iterable of key/value pairs (as tuples or other iterables of length two). If keyword arguments are specified, the dictionary is then updated with those key/value pairs: d.update(red=1, blue=2).
- Changed in version 2.4: Allowed the argument to be an iterable of key/value pairs and allowed keyword arguments.
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所以：
1 | dict1.update(dict2) |