PHP_VERSION_ID是int但未定义。 (PHP-FPM 5.4.4)

PHP_VERSION_ID is int but not defined. (PHP-FPM 5.4.4)

本问题已经有最佳答案，请猛点这里访问。

标题解释了它，但这是我试图做的：

1
2
3

if (!defined(PHP_VERSION_ID) || PHP_VERSION_ID < 50400) {
trigger_error('PHP version 5.4 or above is required to run this code. Please upgrade to continue...', E_USER_ERROR);
}

出于某种原因，这是正在发生的事情：

1 2	var_dump(PHP_VERSION_ID); // returns int(50404) var_dump(defined(PHP_VERSION_ID)); // returns bool(false)

根据defined上的php.net页面，你可以这样做：

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30

<?php
// PHP_VERSION_ID is available as of PHP 5.2.7, if our
// version is lower than that, then emulate it
if (!defined('PHP_VERSION_ID')) {
$version = explode('.', PHP_VERSION);

define('PHP_VERSION_ID', ($version[0] * 10000 + $version[1] * 100 + $version[2]));
}

// PHP_VERSION_ID is defined as a number, where the higher the number
// is, the newer a PHP version is used. It's defined as used in the above
// expression:
//
// $version_id = $major_version * 10000 + $minor_version * 100 + $release_version;
//
// Now with PHP_VERSION_ID we can check for features this PHP version
// may have, this doesn't require to use version_compare() everytime
// you check if the current PHP version may not support a feature.
//
// For example, we may here define the PHP_VERSION_* constants thats
// not available in versions prior to 5.2.7

if (PHP_VERSION_ID < 50207) {
define('PHP_MAJOR_VERSION', $version[0]);
define('PHP_MINOR_VERSION', $version[1]);
define('PHP_RELEASE_VERSION', $version[2]);

// and so on, ...
}
?>

关于为什么这不起作用的任何想法？我在Debian Wheezy上运行PHP-FPM 5.4.4。