关于c＃：派生类中的重载基方法

Overloading base method in derived class

因此，我正在玩C.*，以查看它是否与此帖子中的C++行为相匹配：HTTP://HbbSutTur.COM/2013/05/22/GOTW-5解决方案当我遇到这种奇怪的行为时：

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54

public class BaseClass
{
public virtual void Foo(int i)
{
Console.WriteLine("Called Foo(int):" + i);
}

public void Foo(string i)
{
Console.WriteLine("Called Foo(string):" + i);
}
}

public class DerivedClass : BaseClass
{
public void Foo(double i)
{
Console.WriteLine("Called Foo(double):" + i);
}
}

public class OverriddenDerivedClass : BaseClass
{
public override void Foo(int i)
{
base.Foo(i);
}

public void Foo(double i)
{
Console.WriteLine("Called Foo(double):" + i);
}
}

class Program
{
static void Main(string[] args)
{
DerivedClass derived = new DerivedClass();
OverriddenDerivedClass overridedDerived = new OverriddenDerivedClass();

int i = 1;
double d = 2.0;
string s ="hi";

derived.Foo(i);
derived.Foo(d);
derived.Foo(s);

overridedDerived.Foo(i);
overridedDerived.Foo(d);
overridedDerived.Foo(s);
}
}

产量

1
2
3
4
5
6

Called Foo(double): 1
Called Foo(double): 2
Called Foo(string): hi
Called Foo(double): 1
Called Foo(double): 2
Called Foo(string): hi

显然，它倾向于隐式地将int转换为double，而不是基类中更具体的foo(int)。或者它是否将foo(int)隐藏在基类中？但是：为什么不隐藏foo(字符串)？感觉很不一致…不管我是否重写foo(int)，结果都是一样的。有人能解释一下这是怎么回事吗？

(是的，我知道在派生类(liskov和all)中重载基方法是不好的做法，但是我仍然不希望在overridedEnderivedClass中调用foo(in t)？！)