关于ajax：如何为JQuery .always()函数中的每个语句指定不同的函数

how to specify a different function for each statement in JQuery .always() function

根据官方JQuery文档：

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jqXHR.always(function(data|jqXHR, textStatus, jqXHR|errorThrown) { });

An alternative construct to the complete callback option, the
.always() method replaces the deprecated .complete()method.

In response to a successful request, the function's arguments are the
same as those of .done(): data, textStatus, and the jqXHR object. For
failed requests the arguments are the same as those of .fail(): the
jqXHR object, textStatus, and errorThrown. Refer to deferred.always()
for implementation details.

让我们说我有以下ajax脚本：

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$.ajax({

url: 'myPHPScript.php',
type: 'POST',
data: {
param_1: 'value_1',
param_n: 'value_n'…
},
username: 'myLogin',
password: 'myPassword',
beforeSend: function() {
alert('The object was created but not yet initilized');
}
}).done(function(data, textStatus, jqXHR) {
alert('All the request was sent and we received data');
}).fail(function(jqXHR, textStatus, errorThrown) {
alert('Error: the following error was occurred: ' + textStatus + ' Status : ' + jqXHR.Status);
}).always(function() {
// Here is my problem
});

在.always()函数中，如何为每个语句指定不同的函数，我的意思是当Deferred被解析时，always()函数会传递以下参数(data，textStatus，jqXHR)但是如果延迟被拒绝它被传递(jqXHR，textStatus，errorThrown)。

谢谢