关于sql server：将单个列连接到逗号分隔的列表中

Concatenate a single column into a comma delimited list

本问题已经有最佳答案，请猛点这里访问。

我看到过很多人将一个列汇总成逗号分隔的列表的例子，但我需要更多。

下面是一个我需要的数据和结果的例子。

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DECLARE @SalesPerson table (SalesPersonID int, SalesPersonName varchar(10))
DECLARE @Region table (RegionID int, RegionName varchar(15))
DECLARE @SalesPersonRegion table (SalesPersonID int, RegionID int)

INSERT INTO @SalesPerson (SalesPersonID, SalesPersonName) VALUES (1,'Jeff')
INSERT INTO @SalesPerson (SalesPersonID, SalesPersonName) VALUES (2,'Pat')
INSERT INTO @SalesPerson (SalesPersonID, SalesPersonName) VALUES (3,'Joe')

INSERT INTO @Region (RegionID, RegionName) VALUES (1,'North')
INSERT INTO @Region (RegionID, RegionName) VALUES (2,'South')
INSERT INTO @Region (RegionID, RegionName) VALUES (3,'East')
INSERT INTO @Region (RegionID, RegionName) VALUES (4,'West')

INSERT INTO @SalesPersonRegion (SalesPersonID,RegionID) VALUES (1,1)
INSERT INTO @SalesPersonRegion (SalesPersonID,RegionID) VALUES (1,2)
INSERT INTO @SalesPersonRegion (SalesPersonID,RegionID) VALUES (1,3)
INSERT INTO @SalesPersonRegion (SalesPersonID,RegionID) VALUES (2,2)
INSERT INTO @SalesPersonRegion (SalesPersonID,RegionID) VALUES (2,3)
INSERT INTO @SalesPersonRegion (SalesPersonID,RegionID) VALUES (2,4)
INSERT INTO @SalesPersonRegion (SalesPersonID,RegionID) VALUES (3,1)
INSERT INTO @SalesPersonRegion (SalesPersonID,RegionID) VALUES (3,4)

一个简单的选择可以让我了解每个销售人员，以及每个销售人员所在的地区。

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SELECT
sp.SalesPersonID,
sp.SalesPersonName,
r.RegionName
FROM @SalesPersonRegion spr
JOIN @SalesPerson sp
ON spr.SalesPersonID = sp.SalesPersonID
JOIN @Region r
ON spr.RegionID = r.RegionID

在这种情况下，它将返回9行。

我想得到这样的结果：

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SalesPersonID SalesPersonName Regions
1 Jeff North,South,East
2 Pat South,East,West
3 Joe North,West

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SELECT
sp.SalesPersonID,
sp.SalesPersonName,
Regions = STUFF
(
(
SELECT ',' + r.RegionName
FROM @Region AS r
INNER JOIN @SalesPersonRegion AS spr
ON r.RegionID = spr.RegionID
WHERE spr.SalesPersonID = sp.SalesPersonID
ORDER BY r.RegionID
FOR XML PATH(''), TYPE
).value('.[1]','nvarchar(max)'),
1,1,''
)
FROM @SalesPerson AS sp
ORDER BY sp.SalesPersonID;

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select
sp.SalesPersonID,
sp.SalesPersonName,
stuff(
(
select ',' + r.RegionName
from @SalesPersonRegion as spr
inner join @Region as r on r.RegionID = spr.RegionID
where spr.SalesPersonID = sp.SalesPersonID
for xml path(''), type
).value('.', 'nvarchar(max)')
, 1, 1, '')
from @SalesPerson as sp

SQL的例子湖小提琴

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试试这个查询：

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SELECT
sp.SalesPersonID,
sp.SalesPersonName,
reg.Regions
FROM @SalesPerson sp
CROSS APPLY( -- or OUTER APPLY
SELECT STUFF(
(SELECT ','+r.RegionName
FROM @Region r INNER JOIN @SalesPersonRegion spr ON r.RegionID = spr.RegionID
WHERE spr.SalesPersonID = sp.SalesPersonID
FOR XML PATH('')),1,1,'') AS Regions
)reg;

结果：

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SalesPersonID SalesPersonName Regions
------------- --------------- ----------------
1 Jeff North,South,East
2 Pat South,East,West
3 Joe North,West

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