关于jquery:JqGrid datetime列返回字符串值,如/ Date(1380565800000)而不是DateTime对象

JqGrid datetime column returns string value like /Date(1380565800000) instead of DateTime object

我正在使用具有以下colmodel定义的jqgrid

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colModel: [
        .
        .
        .
        {
            name: 'ReadingTransferTime', index: 'ReadingTransferTime', width: 78, formatter: 'date', formatoptions: { srcformat: 'm/d/Y', newformat: 'm/d/Y' },
            sorttype: 'date', fixed: true, align: 'center'
        },
        .
        .
        .
        {
            name: 'CPAPStatus', index: 'CPAPStatus', sortable: false, align: 'center', formatter: LoadCPAPFollowUpDialog, width: 100, fixed: true,
            cellattr: function (rowId, tv, rawObject, cm, rdata) { return 'style="white-space: normal!important;' }
        },            
        { name: 'CPAPDeliveryReason', hidden: true },
        { name: 'CPAPDeliveredDate', hidden: true },
        { name: 'CPAPDeliveryStatus', hidden: true }
        ],

自定义格式化程序loadcapfollowupdialog如下所示

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function LoadCPAPFollowUpDialog(cellvalue, options, rowObject) {        
var paramList = JSON.stringify({
    ReadingID: rowObject.ReadingID,
    TransferTime:rowObject.ReadingTransferTime,
    PatientName: rowObject.PatientFullName,
    PAPDeliveredDate: rowObject.CPAPDeliveredDate,
    NonDeliveryReason: rowObject.CPAPDeliveryReason,
    GridID:"HSTCandidatesDtls"
});

return"<img src='../Content/images/icons/edit.gif' title='" +"@VirtuOxAdmin.SleepStudyDetails_Image_CPAPStatus" +"' \
onClick='openDialog("SleepStudyDtlsDialog","" +"@VirtuOxAdmin.SleepStudyDetails_Dialog_CPAPStatus" +"","CPAPDelivery"," + paramList +","500","auto")'>" +"<span>" + rowObject.CPAPDeliveryStatus +"</span>";

}

在此列值的格式化程序readingTransferTime&cpapDeliveredDate中,我得到的是/date(1380565800000)/这样的字符串值,而不是datetime对象。这为我的操作方法cpapdelivery接受错误的参数值创建了问题。如何解决这个问题?

我从这里取了1个溶液&将我的ParamList JSON对象格式化为(amp;F)

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var paramList = JSON.stringify({
    ReadingID: rowObject.ReadingID,
    TransferTime:new Date(rowObject.ReadingTransferTime.match(/\d+/)[0]*1),
    PatientName: rowObject.PatientFullName,
    PAPDeliveredDate: (rowObject.CPAPDeliveredDate!=null? new Date(rowObject.CPAPDeliveredDate.match(/\d+/)[0]*1):null),
    NonDeliveryReason: rowObject.CPAPDeliveryReason,
    GridID:"HSTCandidatesDtls"
});

这是解决所述问题的正确方法吗;或者JQGrid有一些内置的功能来处理它。


试试这个,

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 string jsonDate ="/Date(1380565800000)/";
 jsonDate = jsonDate.Replace("/Date(", string.Empty);
 jsonDate = jsonDate.Replace(")/", string.Empty);

 var date = new DateTime(1970, 1, 1, 0, 0, 0, 0).AddMilliseconds(long.Parse(jsonDate));
 date = date.AddDays(1);

希望这有帮助。