POST请求发送json数据java HttpUrlConnection

POST request send json data java HttpUrlConnection

我开发了一个Java代码，它使用URL和HTTPURLCONNECT将以下卷发转换为Java代码。卷曲度为：

1	curl -i 'http://url.com' -X POST -H"Content-Type: application/json" -H"Accept: application/json" -d '{"auth": {"passwordCredentials": {"username":"adm","password":"pwd"},"tenantName":"adm"}}'

我写过这段代码，但它总是给HTTP代码400错误的请求。我找不到丢失的东西。

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String url="http://url.com";
URL object=new URL(url);

HttpURLConnection con = (HttpURLConnection) object.openConnection();
con.setDoOutput(true);
con.setDoInput(true);
con.setRequestProperty("Content-Type","application/json");
con.setRequestProperty("Accept","application/json");
con.setRequestMethod("POST");

JSONObject cred = new JSONObject();
JSONObject auth = new JSONObject();
JSONObject parent = new JSONObject();

cred.put("username","adm");
cred.put("password","pwd");

auth.put("tenantName","adm");
auth.put("passwordCredentials", cred.toString());

parent.put("auth", auth.toString());

OutputStreamWriter wr = new OutputStreamWriter(con.getOutputStream());
wr.write(parent.toString());
wr.flush();

//display what returns the POST request

StringBuilder sb = new StringBuilder();
int HttpResult = con.getResponseCode();
if (HttpResult == HttpURLConnection.HTTP_OK) {
BufferedReader br = new BufferedReader(
new InputStreamReader(con.getInputStream(),"utf-8"));
String line = null;
while ((line = br.readLine()) != null) {
sb.append(line +"
");
}
br.close();
System.out.println("" + sb.toString());
} else {
System.out.println(con.getResponseMessage());
}

号

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private JSONObject uploadToServer() throws IOException, JSONException {
String query ="https://example.com";
String json ="{"key":1}";

URL url = new URL(query);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setConnectTimeout(5000);
conn.setRequestProperty("Content-Type","application/json; charset=UTF-8");
conn.setDoOutput(true);
conn.setDoInput(true);
conn.setRequestMethod("POST");

OutputStream os = conn.getOutputStream();
os.write(json.getBytes("UTF-8"));
os.close();

// read the response
InputStream in = new BufferedInputStream(conn.getInputStream());
String result = org.apache.commons.io.IOUtils.toString(in,"UTF-8");
JSONObject jsonObject = new JSONObject(result);

in.close();
conn.disconnect();

return jsonObject;
}

。

您可以使用此代码通过HTTP和JSON进行连接和请求。

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try {

URL url = new URL("https://www.googleapis.com/youtube/v3/playlistItems?part=snippet"
+"&key=AIzaSyAhONZJpMCBqCfQjFUj21cR2klf6JWbVSo"
+"&access_token=" + access_token);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setDoOutput(true);
conn.setRequestMethod("POST");
conn.setRequestProperty("Content-Type","application/json");

String input ="{ "snippet": {"playlistId": "WL","resourceId": {"videoId": ""+videoId+"","kind": "youtube#video\
<hr>
<p>
the correct answer is good , but
</p>

[cc lang="java"]OutputStreamWriter wr= new OutputStreamWriter(con.getOutputStream());
wr.write(parent.toString());

。

不是为我工作，而是使用：

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byte[] outputBytes = rootJsonObject.getBytes("UTF-8");
OutputStream os = con.getOutputStream();
os.write(outputBytes);