从字符串调用php函数名

call php function name from a string

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我创建了一个PHP函数来返回或保存一些JSON，这个类看起来像这样。

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<?php
class calendarModel {

// global variables
var $user;
var $action;
var $connect;

// init class
function __construct($action ="getEvents") {
$this->user = 1;

$this->action = $action;

$dbhost ="localhost";
$dbport ="5432";
$dbname ="fixevents";
$dbuser ="postgres";
$dbpass ="123";
$this->connect = pg_connect("host=" . $dbhost ." port=" . $dbport ." dbname=" . $dbname ." user=" . $dbuser ." password=" . $dbpass);

$this->executeAction();
}

// action router
function executeAction() {
if($this->action =="getEvents")
$this->getEvents();
else if($this->action =="moveEvent")
$this->moveEvent();
else if($this->action =="insertEvent")
$this->insertEvent();
else if($this->action =="updateEvent")
$this->updateEvent();
else if($this->action =="getCalendars")
$this->getCalendars();
else if($this->action =="toggleCalendar")
$this->toggleCalendar();
else if($this->action =="deleteCalendar")
$this->deleteCalendar();
else if($this->action =="insertCalendar")
$this->insertCalendar();
}

// getEvents
function getEvents() {
//...
}

// moveEvent
function moveEvent() {
//...
}

// insertEvent
function insertEvent() {
//...
}

// updateEvent
function updateEvent() {
//...
}

// toggleCalendar
function toggleCalendar() {
//...
}

// deleteCalendar
function deleteCalendar() {
//...
}

// insertCalendar
function insertCalendar() {
//...
}

}

// call class
if(isset($_GET['action']))
$instance = new calendarModel($_GET['action']);
else
$instance = new calendarModel();
?>

我想知道的是，我是否可以从字符串名称中调用该构造中的操作，而不是将该if/else if函数变为名为executeAction的大if/else if函数。提前谢谢你，丹尼尔！