关于输入：在C ++中使用Switch语句

Using the Switch Statement in C++

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case'1':
{
... // case 1 will require you to input a ID number and a bunch of info..
break;
}

case'2':
{
...// case 2 is gonna search the ID and display the info
break;
}

结果是……

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Whats your choice :1

Enter a ID no. : 0001 //USER is ask to make a ID number
Enter Name : Paolo //USER is ask to enter a Name
Enter Address: blah blah //USER is ask to enter an address

…然后，如果所有输入都被填满，它将返回到菜单。

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whats your choice :2
Enter ID : 0001 //User is ask to enter the ID number he created
Name : paolo // DISPLAY THE NAME
address : blah blah //DISPLAY THE ADDRESS

编辑：修改了我的问题，switch语句能做到吗？

相关讨论

正如我从"如何在不替换第一个ID和信息的情况下输入多个ID和信息"中所理解的。您应该将与每个ID相关联的信息存储在特殊的数组中(例如std:：map)。

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#include <map>
#include <string>
#include <iostream>

using namespace std;

struct IdInfo {
string name;
string address;
};

int main() {

std::map<std::string, IdInfo> idsInfo;

while (true) {
cout <<"
input 1 or 2:";
char input = (int)getchar();
cin.get();
switch (input) {
case '1': {
cout <<"
write id:";
std::string id;
getline(cin, id);
cout <<"
write name:";
std::string name;
getline(cin, name);
cout <<"
write address:";
std::string address;
getline(cin, address);
IdInfo newInfo;
newInfo.name = name;
newInfo.address = address;
idsInfo[id] = newInfo;
break;}
case '2': {
std::string id2;
cout <<"
write id:";
getline(cin, id2);
IdInfo info = idsInfo[id2];
std::cout <<"
info:" << info.name <<"" << info.address;

break;}
default:
// Finish execution.
return 0;
break;
}
}

}