How to delete elements from a list in a dictionary
本问题已经有最佳答案,请猛点这里访问。
我有一本字典,
这是我的字典:
1 | result = {'LoadLevel': [0.212399, 0.393191, 0.727874, 1.347436, 2.494368, 4.617561, 8.548006, 15.824027, 29.293362, 54.227726, 1.0], 'WeightedLevel': [388.850952, 716.718689, 1312.55957, 2405.087158, 4460.083984, 8543.792969, 18805.201172, 57438.140625, 196024.515625, 860072.3125, 1792.367554], 'Blocks': [7255.151855, 231.589661, 9.365415, 0.55364, 0.0504, 0.006408, 0.001204, 0.000842, 0.909091, 1e-06, 2.060041], 'Failure': [2.0, 2.0, 2.0, 2.0, 2.0, 2.0, 2.0, 2.0, 3.0, 3.0, 2.0], 'Job': 'Desktop', 'Task': 'test'} |
试试这个:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 | result = {'LoadLevel': [0.212399, 0.393191, 0.727874, 1.347436, 2.494368, 4.617561, 8.548006, 15.824027, 29.293362, 54.227726, 1.0], 'WeightedLevel': [388.850952, 716.718689, 1312.55957, 2405.087158, 4460.083984, 8543.792969, 18805.201172, 57438.140625, 196024.515625, 860072.3125, 1792.367554], 'Blocks': [7255.151855, 231.589661, 9.365415, 0.55364, 0.0504, 0.006408, 0.001204, 0.000842, 0.909091, 1e-06, 2.060041], 'Failure': [2.0, 2.0, 2.0, 2.0, 2.0, 2.0, 2.0, 2.0, 3.0, 3.0, 2.0], 'Job': 'Desktop', 'Task': 'test'} if result['Failure'][8] == 1.0 or result['Failure'][8] == 3.0: del result['LoadLevel'][8] del result['WeightedLevel'][8] del result['Blocks'][8] del result['Failure'][8] print result |