关于ios：如何将NSString转换为NSArray


how to convert NSString to NSArray

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我有一根绳子

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NSString* str = @"[90, 5, 6]";

我需要把它转换成类似

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NSArray * numbers = [90, 5 , 6];

我这样做了很长一段时间：

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+ (NSArray*) stringToArray:(NSString*)str
{
    NSString *sep = @"[,";
    NSCharacterSet *set = [NSCharacterSet characterSetWithCharactersInString:sep];
    NSArray *temp=[str componentsSeparatedByCharactersInSet:set];

    NSMutableArray* numbers = [[NSMutableArray alloc] init];
    for (NSString* s in temp) {
        NSNumber *n = [NSNumber numberWithInteger:[s integerValue]];
        [numbers addObject:n];
    }

    return numbers;
}

有没有什么简洁快速的方法来进行这种转换？

谢谢

第一remove的unwanted个字符从字符串，像白色的空间和braces： P / < >

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NSString* str = @"[90, 5, 6]";
NSCharacterSet* characterSet = [[NSCharacterSet
                                 characterSetWithCharactersInString:@"0123456789,"] invertedSet];
NSString* newString = [[str componentsSeparatedByCharactersInSet:characterSet]
                       componentsJoinedByString:@""];

你会有一个像这样的字符串：90,5,6。然后用逗号"单纯的病毒分离和convert到NSNumber： P / < >

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NSArray* arrayOfStrings = [newString componentsSeparatedByString:@","];
NSMutableArray* arrayOfNumbers = [NSMutableArray arrayWithCapacity:arrayOfStrings.count];
for (NSString* string in arrayOfStrings) {
    [arrayOfNumbers addObject:[NSDecimalNumber decimalNumberWithString:string]];
}

使用"NSString从这一类反应，它可以简化到： P / < >

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NSArray* arrayOfStrings = [newString componentsSeparatedByString:@","];
NSArray* arrayOfNumbers = [arrayOfStrings valueForKey: @"decimalNumberValue"];
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NSString* str = @"[90, 5, 6]";
NSCharacterSet *characterSet = [NSCharacterSet characterSetWithCharactersInString:@"[]"];
NSArray *array = [[[str componentsSeparatedByCharactersInSet:characterSet]
                        componentsJoinedByString:@""]    
                        componentsSeparatedByString:@","];
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NSString *newSTR = [str stringByReplacingOccurrencesOfString:@"[" withString:@""];

newSTR = [newSTR stringByReplacingOccurrencesOfString:@"]" withString:@""];

NSArray *items = [newSTR componentsSeparatedByString:@","];

你可以实现，使用定期expression P / < >

((0 9)+) P / < >

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NSError* error = nil;
NSString* str = @"[90, 5, 6]";
NSRegularExpression* regex = [NSRegularExpression regularExpressionWithPattern:@"([0-9]+)" options:0 error:&error];
NSArray* matches = [regex matchesInString:str options:0 range:NSMakeRange(0, [str length])];

然后你有nsarray的字符串，你就需要iterate它和convert的字符串插入到数量和他们中的一个阵列。 P / < >

像这样的尝试 P / < >

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NSArray *arr = [string componentsSeparatedByString:@","];
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