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Why ‘this’ is a pointer and not a reference?

在C++中，EDCOX1的0个原因是不是一个指针，而不是历史语言决定的一个引用？考虑到复制构造函数或赋值运算符都接受对"that的引用，而不是指针，这有点奇怪。

[老实说，我找不到这个问题，尽管它看起来可能是重复的]

从Bjarne Stroustrup的《C++的设计与演化》看，Addison Wesley，1994，PP 39－40:

Sometimes, people ask why this is a pointer rather than a reference and why it is called this rather than self. When this was introduced into C with Classes, the language didn't have references, and C++ borrows its terminology from Simula rather than Smalltalk.

创建this时，该语言中不存在引用。