关于 php:SQLSTATE[42000] 聚合函数错误


SQLSTATE[42000] Error on aggregation functions

您好，我在我的 SQL 查询中遇到了一个错误，无法弄清楚是什么问题。这是迄今为止在 Barmar 的帮助下的查询。

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 $query ="SELECT c.*, count(s.curso_id) as count, SUM(IF(s.status = 'aprobado', 1, 0)) AS count_approved , SUM(IF(s.status = 'cupolleno', 1, 0)) AS count_cupolleno
    , SUM(IF(s.status = 'cancelado', 1, 0)) AS count_cancelado, SUM(IF(s.status = 'noacion', 1, 0)) AS count_noacion, SUM(IF(s.status = 'ama_de_casa', 1, 0)) AS count_ama_de_casa
    , SUM(IF(s.status = 'cliente_externo', 1, 0)) AS count_cliente_externo
    FROM cursos_modulos AS c
    LEFT JOIN subscriptions AS s ON s.curso_id = c.id
    LEFT JOIN users AS u ON u.userID = s.user_id GROUP BY c.id WHERE 1";
                if (!empty($id)) { $query .=" AND c.id = '$id'"; }
                if (!empty($ciudad)) { $query .=" AND c.ciudad = '$ciudad'"; }
                if (!empty($tipo)) { $query .=" AND c.tipo = '$tipo'"; }
                if (!empty($titulo))  { $query .=" AND c.titulo = '$titulo'"; }
                if (!empty($status))  { $query .=" AND c.status = '$status'"; }
 $paginate = new pagination($page, $query, $options);

我得到的错误信息如下：

Fatal error: Uncaught exception 'PDOException' with message
'SQLSTATE[42000]: Syntax error or access violation: 1064 You have an
error in your SQL syntax; check the manual that corresponds to your
MySQL server version for the right syntax to use near 'WHERE 1 AND
c.id = '1' LIMIT 0, 30' at line 6' in
E:\\xampp\\htdocs\\admin\\class\\pagination.php:376 Stack trace: #0
E:\\xampp\\htdocs\\admin\\class\\pagination.php(376):
PDOStatement->execute() #1
E:\\xampp\\htdocs\\admin\\class\\pagination.php(202):
pagination->excecute_query() #2
E:\\xampp\\htdocs\\admin\\class\\pagination.php(162):
pagination->run(1, 'SELECT c., cou...', Array) #3
E:\\xampp\\htdocs\\admin\\search.php(146):
pagination->__construct(1, 'SELECT c., cou...', Array) #4 {main}
thrown in E:\\xampp\\htdocs\\admin\\class\\pagination.php on line
376

group by 子句应该在 where 子句之后。即：

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$query ="SELECT c.*, count(s.curso_id) as count, SUM(IF(s.status = 'aprobado', 1, 0)) AS count_approved , SUM(IF(s.status = 'cupolleno', 1, 0)) AS count_cupolleno
, SUM(IF(s.status = 'cancelado', 1, 0)) AS count_cancelado, SUM(IF(s.status = 'noacion', 1, 0)) AS count_noacion, SUM(IF(s.status = 'ama_de_casa', 1, 0)) AS count_ama_de_casa
, SUM(IF(s.status = 'cliente_externo', 1, 0)) AS count_cliente_externo
FROM cursos_modulos AS c
LEFT JOIN subscriptions AS s ON s.curso_id = c.id
LEFT JOIN users AS u ON u.userID = s.user_id WHERE 1";
            if (!empty($id)) { $query .=" AND c.id = '$id'"; }
            if (!empty($ciudad)) { $query .=" AND c.ciudad = '$ciudad'"; }
            if (!empty($tipo)) { $query .=" AND c.tipo = '$tipo'"; }
            if (!empty($titulo))  { $query .=" AND c.titulo = '$titulo'"; }
            if (!empty($status))  { $query .=" AND c.status = '$status'"; }
$query .=" GROUP BY c.id";
相关讨论

where 1 能为你做什么？尝试杀死它。

以下不会引发 1064 错误：

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create table cursos_modulos
(   id int not null

);

create table subscriptions
(   curso_id int not null,
    user_id int not null,
    status varchar(100) not null
);

create table users
(   userID int not null
);

SELECT c.id,
count(s.curso_id) as count,
SUM(IF(s.status = 'aprobado', 1, 0)) AS count_approved,
SUM(IF(s.status = 'cupolleno', 1, 0)) AS count_cupolleno,
SUM(IF(s.status = 'cancelado', 1, 0)) AS count_cancelado,
SUM(IF(s.status = 'noacion', 1, 0)) AS count_noacion,
SUM(IF(s.status = 'ama_de_casa', 1, 0)) AS count_ama_de_casa,
SUM(IF(s.status = 'cliente_externo', 1, 0)) AS count_cliente_externo
FROM cursos_modulos AS c
LEFT JOIN subscriptions AS s ON s.curso_id = c.id
LEFT JOIN users AS u ON u.userID = s.user_id
GROUP BY c.id
相关讨论