Printing Loop into a Text file
本问题已经有最佳答案，请猛点这里访问。
我想把它打印到一个文本文件中，但是我环顾四周，不知道该怎么做。
1 2 3 4 5 6 7 8 9 10 11 12 13 | def countdown (n): while (n > 1): print(' ',(n), 'Bottles of beer on the wall,', (n), 'bottles of beer, take one down pass it around', (n)-1, 'bottles of beer on the wall.') n -= 1 if (n == 2): print(' ',(n), 'Bottles of beer on the wall,', (n), 'bottles of beer, take one down pass it around', (n)-1, 'bottle of beer on the wall.') else: print (' ',(n), 'Bottle of beer on the wall,', (n), 'bottle of beer, take one down pass it around no more bottles of beer on the wall.') countdown (10) |
而不是。。。
1 2 | ... print('123', '456') |
使用…
1 2 3 4 5 | myFile = open('123.txt', 'w') ... print('123', '456', file = myFile) ... myFile.close() # Remember this out! |
甚至…
1 2 3 4 | with open('123.txt', 'w') as myFile: print('123', '456', file = myFile) # With `with`, you don't have to close the file manually, yay! |
我希望这能给你点启发！
更为"正确"的是，它将被视为写入文本文件。您可以这样编码：
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 | def countdown (n): # Open a file in write mode file = open( 'file name', 'w') while (n > 1): file.write(' ',(n), 'Bottles of beer on the wall,', (n), 'bottles of beer, take one down pass it around', (n)-1, 'bottles of beer on the wall.') n -= 1 if (n == 2): file.write(' ',(n), 'Bottles of beer on the wall,', (n), 'bottles of beer, take one down pass it around', (n)-1, 'bottle of beer on the wall.') else: file.write(' ',(n), 'Bottle of beer on the wall,', (n), 'bottle of beer, take one down pass it around no more bottles of beer on the wall.') # Make sure to close the file, or it might not be written correctly. file.close() countdown (10) |