How can I cast from []interface{} to []int?
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我想得到不重复的。我用的是
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 | package main import ( "fmt" "math/rand" "time" "github.com/deckarep/golang-set" ) func pickup(max int, num int) []int { set := mapset.NewSet() rand.Seed(time.Now().UnixNano()) for set.Cardinality() < num { n := rand.Intn(max) set.Add(n) } selected := set.ToSlice() // Do I need to cast from []interface{} to []int around here? // selected.([]int) is error. return selected } func main() { results := pickup(100, 10) fmt.Println(results) // some processing using []int... } |
没有自动的方法可以做到这一点。您需要创建一个int切片并复制到其中：
1 2 3 4 5 6 7 8 9 10 11 | selected := set.ToSlice() // create a secondary slice of ints, same length as selected ret := make([]int, len(selected)) // copy one by one for i, x := range selected { ret[i] = x.(int) //provided it's indeed int. you can add a check here } return ret |