three button keyCode hotkey javascript
来自另一个 stackoverflow 帖子(如何将 JavaScript 键盘快捷键添加到现有 JavaScript 函数?)我有这个热键代码:
1 2 3 4 5 6 7
| function doc_keyPress(e) {
if (e.shiftKey && e.keyCode == 80) {
//do something
}
}
document.addEventListener('keyup', doc_keyPress, false); |
使用两个键。但是使用三个键,例如 shift l m,它不起作用。
if 语句是:
1
| if (e.shiftKey && e.keyCode == 76 && e.keyCode == 77) {} |
再一次,这不起作用。
我如何让这个工作为 shift l m.
- e.shiftKey && e.keyCode == 76 && e.keyCode == 77 - 只有当 keyCode 是两个不同的值(76
-
使用闭包,我想你可以做这样的事情
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28
| var doc_keypress = (function() {
var prevWasL = false;
return function(e) {
if (e.type == 'keypress') {
if (e.shiftKey && !(e.ctrlKey || e.metaKey)) {
if (prevWasL) {
if (e.charCode == 77) {
console.log('doing it');
prevWasL = false;
return;
}
}
if (e.charCode == 76) {
prevWasL = true;
return;
}
}
prevWasL = false;
} else { // keyup
if (e.key == 'Shift') {
prevWasL = false;
}
}
}
}());
document.addEventListener('keypress', doc_keypress);
document.addEventListener('keyup', doc_keypress); |
同时添加 keypress 和 keyup 事件侦听器,以便
的场景
Shift L,同时释放,Shift M,不会触发误报
这需要 shift 然后按 L 然后按 M 的顺序...如果你想要 L 和 M 的任何一个顺序,那么代码会有点不同,但你应该能够弄清楚
NOTE: I use charCode, because firefox at least, keyCode is always 0 on keyPress event
434511
棘手,棘手,但我设法让它工作。请注意,浏览器有自己的热键(如 chrome [ctrl] [shift] i),它可能会覆盖该功能。
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30
| <!DOCTYPE html>
<html>
<body>
<input id="myInput" onkeydown="keyDownEvent(event)" onkeyup="resetKeys()">
</body>
</html>
var key1Pressed=false;
var key2Pressed=false;
function resetKeys(){
key1Pressed=false;
key2Pressed=false;
}
function keyDownEvent(e){
e=e||event, chrCode=(typeof e.which=="number")?e.which:e.keyCode;
if (e.shiftKey && chrCode === 76) key1Pressed=true;
if (e.shiftKey && chrCode === 77) key2Pressed=true;
if(key1Pressed && key2Pressed){
alert('Three Keys Are Pressed');
key1Pressed=false;
key2Pressed=false;
}
}
document.getElementById('myInput').focus(); |
434511
如果您尝试双击或三次按键并在此之后捕获事件,我已经编写了一个简单的帮助程序:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28
| function KeyPress(_opts) {
this.opts = Object.assign({}, {
counts: {},
timeouts: {},
timeBetweenPresses: 300
}, _opts || {});
}
KeyPress.prototype.bubbledReset = function bubbledReset(keyCode) {
var self = this;
if (this.opts.timeouts[keyCode]) {
clearTimeout(this.opts.timeouts[keyCode]);
this.opts.timeouts[keyCode] = 0;
}
this.opts.timeouts[keyCode] = setTimeout(function () {
self.opts.counts[keyCode] = 0;
}, this.opts.timeBetweenPresses);
};
KeyPress.prototype.onTap = function onTap(cb) {
var self = this;
return function handler(event) {
self.opts.counts[event.keyCode] = self.opts.counts[event.keyCode] || 0;
self.opts.counts[event.keyCode]++;
self.bubbledReset(event.keyCode);
cb(event.keyCode, self.opts.counts[event.keyCode]);
};
}; |
用法
只需使用 onTap 方法实例化:
1 2 3 4 5 6 7 8 9 10
| var keyPress = new KeyPress();
document.addEventListener('keyup', keyPress.onTap(function (keyCode, count) {
if (keyCode === 68 && count === 3) {
// 68 was tapped 3 times (D key)
}
if (keyCode === 13 && count === 6) {
// 13 was tapped 6 times (ENTER key)
}
})); |
希望这对其他人有帮助!
或者如果你喜欢 es6:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29
| class KeyPress {
constructor(_opts) {
this.opts = Object.assign({}, {
counts: {},
timeouts: {},
timeBetweenPresses: 300
}, _opts || {});
}
bubbledReset(keyCode) {
if (this.timeouts[keyCode]) {
clearTimeout(this.timeouts[keyCode]);
this.timeouts[keyCode] = 0;
}
this.timeouts[keyCode] = setTimeout(() => {
this.counts[keyCode] = 0;
}, this.timeBetweenPresses);
}
onTap(cb) {
return event => {
this.counts[event.keyCode] = this.counts[event.keyCode] || 0;
this.counts[event.keyCode]++;
this.bubbledReset(event.keyCode);
cb(event.keyCode, this.counts[event.keyCode]);
};
}
} |
-
使用闭包,我想你可以做这样的事情
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28
| var doc_keypress = (function() {
var prevWasL = false;
return function(e) {
if (e.type == 'keypress') {
if (e.shiftKey && !(e.ctrlKey || e.metaKey)) {
if (prevWasL) {
if (e.charCode == 77) {
console.log('doing it');
prevWasL = false;
return;
}
}
if (e.charCode == 76) {
prevWasL = true;
return;
}
}
prevWasL = false;
} else { // keyup
if (e.key == 'Shift') {
prevWasL = false;
}
}
}
}());
document.addEventListener('keypress', doc_keypress);
document.addEventListener('keyup', doc_keypress); |
同时添加 keypress 和 keyup 事件侦听器,以便
的场景
Shift L,同时释放,Shift M,不会触发误报
这需要 shift 然后按 L 然后按 M 的顺序...如果你想要 L 和 M 的任何一个顺序,那么代码会有点不同,但你应该能够弄清楚
NOTE: I use charCode, because firefox at least, keyCode is always 0 on keyPress event
434511
棘手,棘手,但我设法让它工作。请注意,浏览器有自己的热键(如 chrome [ctrl] [shift] i),它可能会覆盖该功能。
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30
| <!DOCTYPE html>
<html>
<body>
<input id="myInput" onkeydown="keyDownEvent(event)" onkeyup="resetKeys()">
</body>
</html>
var key1Pressed=false;
var key2Pressed=false;
function resetKeys(){
key1Pressed=false;
key2Pressed=false;
}
function keyDownEvent(e){
e=e||event, chrCode=(typeof e.which=="number")?e.which:e.keyCode;
if (e.shiftKey && chrCode === 76) key1Pressed=true;
if (e.shiftKey && chrCode === 77) key2Pressed=true;
if(key1Pressed && key2Pressed){
alert('Three Keys Are Pressed');
key1Pressed=false;
key2Pressed=false;
}
}
document.getElementById('myInput').focus(); |
434511
如果您尝试双击或三次按键并在此之后捕获事件,我已经编写了一个简单的帮助程序:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28
| function KeyPress(_opts) {
this.opts = Object.assign({}, {
counts: {},
timeouts: {},
timeBetweenPresses: 300
}, _opts || {});
}
KeyPress.prototype.bubbledReset = function bubbledReset(keyCode) {
var self = this;
if (this.opts.timeouts[keyCode]) {
clearTimeout(this.opts.timeouts[keyCode]);
this.opts.timeouts[keyCode] = 0;
}
this.opts.timeouts[keyCode] = setTimeout(function () {
self.opts.counts[keyCode] = 0;
}, this.opts.timeBetweenPresses);
};
KeyPress.prototype.onTap = function onTap(cb) {
var self = this;
return function handler(event) {
self.opts.counts[event.keyCode] = self.opts.counts[event.keyCode] || 0;
self.opts.counts[event.keyCode]++;
self.bubbledReset(event.keyCode);
cb(event.keyCode, self.opts.counts[event.keyCode]);
};
}; |
用法
只需使用 onTap 方法实例化:
1 2 3 4 5 6 7 8 9 10
| var keyPress = new KeyPress();
document.addEventListener('keyup', keyPress.onTap(function (keyCode, count) {
if (keyCode === 68 && count === 3) {
// 68 was tapped 3 times (D key)
}
if (keyCode === 13 && count === 6) {
// 13 was tapped 6 times (ENTER key)
}
})); |
希望这对其他人有帮助!
或者如果你喜欢 es6:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29
| class KeyPress {
constructor(_opts) {
this.opts = Object.assign({}, {
counts: {},
timeouts: {},
timeBetweenPresses: 300
}, _opts || {});
}
bubbledReset(keyCode) {
if (this.timeouts[keyCode]) {
clearTimeout(this.timeouts[keyCode]);
this.timeouts[keyCode] = 0;
}
this.timeouts[keyCode] = setTimeout(() => {
this.counts[keyCode] = 0;
}, this.timeBetweenPresses);
}
onTap(cb) {
return event => {
this.counts[event.keyCode] = this.counts[event.keyCode] || 0;
this.counts[event.keyCode]++;
this.bubbledReset(event.keyCode);
cb(event.keyCode, this.counts[event.keyCode]);
};
}
} |
-
使用闭包,我想你可以做这样的事情
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28
| var doc_keypress = (function() {
var prevWasL = false;
return function(e) {
if (e.type == 'keypress') {
if (e.shiftKey && !(e.ctrlKey || e.metaKey)) {
if (prevWasL) {
if (e.charCode == 77) {
console.log('doing it');
prevWasL = false;
return;
}
}
if (e.charCode == 76) {
prevWasL = true;
return;
}
}
prevWasL = false;
} else { // keyup
if (e.key == 'Shift') {
prevWasL = false;
}
}
}
}());
document.addEventListener('keypress', doc_keypress);
document.addEventListener('keyup', doc_keypress); |
同时添加 keypress 和 keyup 事件侦听器,以便
的场景
Shift L,同时释放,Shift M,不会触发误报
这需要 shift 然后按 L 然后按 M 的顺序...如果你想要 L 和 M 的任何一个顺序,那么代码会有点不同,但你应该能够弄清楚
NOTE: I use charCode, because firefox at least, keyCode is always 0 on keyPress event
434511
棘手,棘手,但我设法让它工作。请注意,浏览器有自己的热键(如 chrome [ctrl] [shift] i),它可能会覆盖该功能。
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30
| <!DOCTYPE html>
<html>
<body>
<input id="myInput" onkeydown="keyDownEvent(event)" onkeyup="resetKeys()">
</body>
</html>
var key1Pressed=false;
var key2Pressed=false;
function resetKeys(){
key1Pressed=false;
key2Pressed=false;
}
function keyDownEvent(e){
e=e||event, chrCode=(typeof e.which=="number")?e.which:e.keyCode;
if (e.shiftKey && chrCode === 76) key1Pressed=true;
if (e.shiftKey && chrCode === 77) key2Pressed=true;
if(key1Pressed && key2Pressed){
alert('Three Keys Are Pressed');
key1Pressed=false;
key2Pressed=false;
}
}
document.getElementById('myInput').focus(); |
434511
如果您尝试双击或三次按键并在此之后捕获事件,我已经编写了一个简单的帮助程序:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28
| function KeyPress(_opts) {
this.opts = Object.assign({}, {
counts: {},
timeouts: {},
timeBetweenPresses: 300
}, _opts || {});
}
KeyPress.prototype.bubbledReset = function bubbledReset(keyCode) {
var self = this;
if (this.opts.timeouts[keyCode]) {
clearTimeout(this.opts.timeouts[keyCode]);
this.opts.timeouts[keyCode] = 0;
}
this.opts.timeouts[keyCode] = setTimeout(function () {
self.opts.counts[keyCode] = 0;
}, this.opts.timeBetweenPresses);
};
KeyPress.prototype.onTap = function onTap(cb) {
var self = this;
return function handler(event) {
self.opts.counts[event.keyCode] = self.opts.counts[event.keyCode] || 0;
self.opts.counts[event.keyCode]++;
self.bubbledReset(event.keyCode);
cb(event.keyCode, self.opts.counts[event.keyCode]);
};
}; |
用法
只需使用 onTap 方法实例化:
1 2 3 4 5 6 7 8 9 10
| var keyPress = new KeyPress();
document.addEventListener('keyup', keyPress.onTap(function (keyCode, count) {
if (keyCode === 68 && count === 3) {
// 68 was tapped 3 times (D key)
}
if (keyCode === 13 && count === 6) {
// 13 was tapped 6 times (ENTER key)
}
})); |
希望这对其他人有帮助!
或者如果你喜欢 es6:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29
| class KeyPress {
constructor(_opts) {
this.opts = Object.assign({}, {
counts: {},
timeouts: {},
timeBetweenPresses: 300
}, _opts || {});
}
bubbledReset(keyCode) {
if (this.timeouts[keyCode]) {
clearTimeout(this.timeouts[keyCode]);
this.timeouts[keyCode] = 0;
}
this.timeouts[keyCode] = setTimeout(() => {
this.counts[keyCode] = 0;
}, this.timeBetweenPresses);
}
onTap(cb) {
return event => {
this.counts[event.keyCode] = this.counts[event.keyCode] || 0;
this.counts[event.keyCode]++;
this.bubbledReset(event.keyCode);
cb(event.keyCode, this.counts[event.keyCode]);
};
}
} |
-
使用闭包,我想你可以做这样的事情
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28
| var doc_keypress = (function() {
var prevWasL = false;
return function(e) {
if (e.type == 'keypress') {
if (e.shiftKey && !(e.ctrlKey || e.metaKey)) {
if (prevWasL) {
if (e.charCode == 77) {
console.log('doing it');
prevWasL = false;
return;
}
}
if (e.charCode == 76) {
prevWasL = true;
return;
}
}
prevWasL = false;
} else { // keyup
if (e.key == 'Shift') {
prevWasL = false;
}
}
}
}());
document.addEventListener('keypress', doc_keypress);
document.addEventListener('keyup', doc_keypress); |
同时添加 keypress 和 keyup 事件侦听器,以便
的场景
Shift L,同时释放,Shift M,不会触发误报
这需要 shift 然后按 L 然后按 M 的顺序...如果你想要 L 和 M 的任何一个顺序,那么代码会有点不同,但你应该能够弄清楚
NOTE: I use charCode, because firefox at least, keyCode is always 0 on keyPress event
434511
棘手,棘手,但我设法让它工作。请注意,浏览器有自己的热键(如 chrome [ctrl] [shift] i),它可能会覆盖该功能。
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30
| <!DOCTYPE html>
<html>
<body>
<input id="myInput" onkeydown="keyDownEvent(event)" onkeyup="resetKeys()">
</body>
</html>
var key1Pressed=false;
var key2Pressed=false;
function resetKeys(){
key1Pressed=false;
key2Pressed=false;
}
function keyDownEvent(e){
e=e||event, chrCode=(typeof e.which=="number")?e.which:e.keyCode;
if (e.shiftKey && chrCode === 76) key1Pressed=true;
if (e.shiftKey && chrCode === 77) key2Pressed=true;
if(key1Pressed && key2Pressed){
alert('Three Keys Are Pressed');
key1Pressed=false;
key2Pressed=false;
}
}
document.getElementById('myInput').focus(); |
434511
如果您尝试双击或三次按键并在此之后捕获事件,我已经编写了一个简单的帮助程序:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28
| function KeyPress(_opts) {
this.opts = Object.assign({}, {
counts: {},
timeouts: {},
timeBetweenPresses: 300
}, _opts || {});
}
KeyPress.prototype.bubbledReset = function bubbledReset(keyCode) {
var self = this;
if (this.opts.timeouts[keyCode]) {
clearTimeout(this.opts.timeouts[keyCode]);
this.opts.timeouts[keyCode] = 0;
}
this.opts.timeouts[keyCode] = setTimeout(function () {
self.opts.counts[keyCode] = 0;
}, this.opts.timeBetweenPresses);
};
KeyPress.prototype.onTap = function onTap(cb) {
var self = this;
return function handler(event) {
self.opts.counts[event.keyCode] = self.opts.counts[event.keyCode] || 0;
self.opts.counts[event.keyCode]++;
self.bubbledReset(event.keyCode);
cb(event.keyCode, self.opts.counts[event.keyCode]);
};
}; |
用法
只需使用 onTap 方法实例化:
1 2 3 4 5 6 7 8 9 10
| var keyPress = new KeyPress();
document.addEventListener('keyup', keyPress.onTap(function (keyCode, count) {
if (keyCode === 68 && count === 3) {
// 68 was tapped 3 times (D key)
}
if (keyCode === 13 && count === 6) {
// 13 was tapped 6 times (ENTER key)
}
})); |
希望这对其他人有帮助!
或者如果你喜欢 es6:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29
| class KeyPress {
constructor(_opts) {
this.opts = Object.assign({}, {
counts: {},
timeouts: {},
timeBetweenPresses: 300
}, _opts || {});
}
bubbledReset(keyCode) {
if (this.timeouts[keyCode]) {
clearTimeout(this.timeouts[keyCode]);
this.timeouts[keyCode] = 0;
}
this.timeouts[keyCode] = setTimeout(() => {
this.counts[keyCode] = 0;
}, this.timeBetweenPresses);
}
onTap(cb) {
return event => {
this.counts[event.keyCode] = this.counts[event.keyCode] || 0;
this.counts[event.keyCode]++;
this.bubbledReset(event.keyCode);
cb(event.keyCode, this.counts[event.keyCode]);
};
}
} |
-
使用闭包,我想你可以做这样的事情
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28
| var doc_keypress = (function() {
var prevWasL = false;
return function(e) {
if (e.type == 'keypress') {
if (e.shiftKey && !(e.ctrlKey || e.metaKey)) {
if (prevWasL) {
if (e.charCode == 77) {
console.log('doing it');
prevWasL = false;
return;
}
}
if (e.charCode == 76) {
prevWasL = true;
return;
}
}
prevWasL = false;
} else { // keyup
if (e.key == 'Shift') {
prevWasL = false;
}
}
}
}());
document.addEventListener('keypress', doc_keypress);
document.addEventListener('keyup', doc_keypress); |
同时添加 keypress 和 keyup 事件侦听器,以便
的场景
Shift L,同时释放,Shift M,不会触发误报
这需要 shift 然后按 L 然后按 M 的顺序...如果你想要 L 和 M 的任何一个顺序,那么代码会有点不同,但你应该能够弄清楚
NOTE: I use charCode, because firefox at least, keyCode is always 0 on keyPress event
434511
棘手,棘手,但我设法让它工作。请注意,浏览器有自己的热键(如 chrome [ctrl] [shift] i),它可能会覆盖该功能。
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30
| <!DOCTYPE html>
<html>
<body>
<input id="myInput" onkeydown="keyDownEvent(event)" onkeyup="resetKeys()">
</body>
</html>
var key1Pressed=false;
var key2Pressed=false;
function resetKeys(){
key1Pressed=false;
key2Pressed=false;
}
function keyDownEvent(e){
e=e||event, chrCode=(typeof e.which=="number")?e.which:e.keyCode;
if (e.shiftKey && chrCode === 76) key1Pressed=true;
if (e.shiftKey && chrCode === 77) key2Pressed=true;
if(key1Pressed && key2Pressed){
alert('Three Keys Are Pressed');
key1Pressed=false;
key2Pressed=false;
}
}
document.getElementById('myInput').focus(); |
434511
如果您尝试双击或三次按键并在此之后捕获事件,我已经编写了一个简单的帮助程序:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28
| function KeyPress(_opts) {
this.opts = Object.assign({}, {
counts: {},
timeouts: {},
timeBetweenPresses: 300
}, _opts || {});
}
KeyPress.prototype.bubbledReset = function bubbledReset(keyCode) {
var self = this;
if (this.opts.timeouts[keyCode]) {
clearTimeout(this.opts.timeouts[keyCode]);
this.opts.timeouts[keyCode] = 0;
}
this.opts.timeouts[keyCode] = setTimeout(function () {
self.opts.counts[keyCode] = 0;
}, this.opts.timeBetweenPresses);
};
KeyPress.prototype.onTap = function onTap(cb) {
var self = this;
return function handler(event) {
self.opts.counts[event.keyCode] = self.opts.counts[event.keyCode] || 0;
self.opts.counts[event.keyCode]++;
self.bubbledReset(event.keyCode);
cb(event.keyCode, self.opts.counts[event.keyCode]);
};
}; |
用法
只需使用 onTap 方法实例化:
1 2 3 4 5 6 7 8 9 10
| var keyPress = new KeyPress();
document.addEventListener('keyup', keyPress.onTap(function (keyCode, count) {
if (keyCode === 68 && count === 3) {
// 68 was tapped 3 times (D key)
}
if (keyCode === 13 && count === 6) {
// 13 was tapped 6 times (ENTER key)
}
})); |
希望这对其他人有帮助!
或者如果你喜欢 es6:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29
| class KeyPress {
constructor(_opts) {
this.opts = Object.assign({}, {
counts: {},
timeouts: {},
timeBetweenPresses: 300
}, _opts || {});
}
bubbledReset(keyCode) {
if (this.timeouts[keyCode]) {
clearTimeout(this.timeouts[keyCode]);
this.timeouts[keyCode] = 0;
}
this.timeouts[keyCode] = setTimeout(() => {
this.counts[keyCode] = 0;
}, this.timeBetweenPresses);
}
onTap(cb) {
return event => {
this.counts[event.keyCode] = this.counts[event.keyCode] || 0;
this.counts[event.keyCode]++;
this.bubbledReset(event.keyCode);
cb(event.keyCode, this.counts[event.keyCode]);
};
}
} |
棘手,棘手,但我设法让它工作。请注意,浏览器有自己的热键(如 chrome [ctrl] [shift] i),它可能会覆盖该功能。
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| <!DOCTYPE html>
<html>
<body>
<input id="myInput" onkeydown="keyDownEvent(event)" onkeyup="resetKeys()">
</body>
</html>
var key1Pressed=false;
var key2Pressed=false;
function resetKeys(){
key1Pressed=false;
key2Pressed=false;
}
function keyDownEvent(e){
e=e||event, chrCode=(typeof e.which=="number")?e.which:e.keyCode;
if (e.shiftKey && chrCode === 76) key1Pressed=true;
if (e.shiftKey && chrCode === 77) key2Pressed=true;
if(key1Pressed && key2Pressed){
alert('Three Keys Are Pressed');
key1Pressed=false;
key2Pressed=false;
}
}
document.getElementById('myInput').focus(); |
使用闭包,我想你可以做这样的事情
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| var doc_keypress = (function() {
var prevWasL = false;
return function(e) {
if (e.type == 'keypress') {
if (e.shiftKey && !(e.ctrlKey || e.metaKey)) {
if (prevWasL) {
if (e.charCode == 77) {
console.log('doing it');
prevWasL = false;
return;
}
}
if (e.charCode == 76) {
prevWasL = true;
return;
}
}
prevWasL = false;
} else { // keyup
if (e.key == 'Shift') {
prevWasL = false;
}
}
}
}());
document.addEventListener('keypress', doc_keypress);
document.addEventListener('keyup', doc_keypress); |
同时添加 keypress 和 keyup 事件侦听器,以便
的场景
Shift L,同时释放,Shift M,不会触发误报
这需要 shift 然后按 L 然后按 M 的顺序...如果你想要 L 和 M 的任何一个顺序,那么代码会有点不同,但你应该能够弄清楚
NOTE: I use charCode, because firefox at least, keyCode is always 0 on keyPress event
如果您尝试双击或三次按键并在此之后捕获事件,我已经编写了一个简单的帮助程序:
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| function KeyPress(_opts) {
this.opts = Object.assign({}, {
counts: {},
timeouts: {},
timeBetweenPresses: 300
}, _opts || {});
}
KeyPress.prototype.bubbledReset = function bubbledReset(keyCode) {
var self = this;
if (this.opts.timeouts[keyCode]) {
clearTimeout(this.opts.timeouts[keyCode]);
this.opts.timeouts[keyCode] = 0;
}
this.opts.timeouts[keyCode] = setTimeout(function () {
self.opts.counts[keyCode] = 0;
}, this.opts.timeBetweenPresses);
};
KeyPress.prototype.onTap = function onTap(cb) {
var self = this;
return function handler(event) {
self.opts.counts[event.keyCode] = self.opts.counts[event.keyCode] || 0;
self.opts.counts[event.keyCode]++;
self.bubbledReset(event.keyCode);
cb(event.keyCode, self.opts.counts[event.keyCode]);
};
}; |
用法
只需使用 onTap 方法实例化:
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| var keyPress = new KeyPress();
document.addEventListener('keyup', keyPress.onTap(function (keyCode, count) {
if (keyCode === 68 && count === 3) {
// 68 was tapped 3 times (D key)
}
if (keyCode === 13 && count === 6) {
// 13 was tapped 6 times (ENTER key)
}
})); |
希望这对其他人有帮助!
或者如果你喜欢 es6:
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| class KeyPress {
constructor(_opts) {
this.opts = Object.assign({}, {
counts: {},
timeouts: {},
timeBetweenPresses: 300
}, _opts || {});
}
bubbledReset(keyCode) {
if (this.timeouts[keyCode]) {
clearTimeout(this.timeouts[keyCode]);
this.timeouts[keyCode] = 0;
}
this.timeouts[keyCode] = setTimeout(() => {
this.counts[keyCode] = 0;
}, this.timeBetweenPresses);
}
onTap(cb) {
return event => {
this.counts[event.keyCode] = this.counts[event.keyCode] || 0;
this.counts[event.keyCode]++;
this.bubbledReset(event.keyCode);
cb(event.keyCode, this.counts[event.keyCode]);
};
}
} |