关于spring：org.hibernate.MappingException：无法确定：java.util.List的类型，在表：user，对于列：[org.hibernate.mapping.Column（events）]

org.hibernate.MappingException: Could not determine type for: java.util.List, at table: user, for columns: [org.hibernate.mapping.Column(events)]

它给了我下面的错误。

1	org.hibernate.MappingException: Could not determine type for: java.util.List, at table: user, for columns: [org.hibernate.mapping.Column(events)]

这里是我的代码

java用户：

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import com.google.common.base.Objects;

import java.util.List;

import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.Id;
import javax.validation.constraints.NotNull;
import javax.validation.constraints.Size;

@Entity
public class User {

@Id
@NotNull
@Size(max = 64)
@Column(name ="id", nullable = false, updatable = false)
private String id;

@NotNull
@Size(max = 64)
@Column(name ="name", nullable = false)
private String name;

@NotNull
@Size(max = 64)
@Column(name ="firstname", nullable = false)
private String firstname;

@NotNull
@Size(max = 64)
@Column(name ="email", nullable = false)
private String email;

@NotNull
@Size(max = 64)
@Column(name ="password", nullable = false)
private String password;

private List<Events> events;

public User() {
}

public User(String id, String name, String firstname, String email, String password) {
super();
this.id = id;
this.name = name;
this.firstname = firstname;
this.email = email;
this.password = password;
}

public void setId(String id) {
this.id = id;
}

public String getId() {
return id;
}

public String getPassword() {
return password;
}

public void setPassword(String password) {
this.password = password;
}

public String getName() {
return name;
}

public void setName(String name) {
this.name = name;
}

public String getFirstname() {
return firstname;
}

public void setFirstname(String firstname) {
this.firstname = firstname;
}

public String getEmail() {
return email;
}

public void setEmail(String email) {
this.email = email;
}

public List<Events> getEvents() {
return events;
}

public void setEvents(List<Events> events) {
this.events = events;
}

@Override
public String toString() {
return Objects.toStringHelper(this).add("id", id).add("name", name).add("firstname", firstname)
.add("email", email).add("password", password).add("events", events).toString();
}
}

号

事件.java：

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public class Events {

public Events() {
}

private String startEvent;
private String endEvent;

public String getStartEvent() {
return startEvent;
}

public void setStartEvent(String startEvent) {
this.startEvent = startEvent;
}

public String getEndEvent() {
return endEvent;
}

public void setEndEvent(String endEvent) {
this.endEvent = endEvent;
}

}

事件不应存储在数据库中

从代码的外观来看，在我看来，事件不应该存储在数据库中。

如果是这种情况，那么标记它们就足够了@transient

1 2	@Transient private List<Events> events;

。