关于java：如何将数组中的文件连接到新文件夹？

How to concatenate files from an array to into a new folder?

本问题已经有最佳答案，请猛点这里访问。

我正在尝试编写一个Java程序，它将采用两个参数，EDCOX1，0，EDCX1，1。程序将搜索以.java结尾的dirName中的所有文件，然后将它们连接到名为fileName的新文件夹中。到目前为止，我有一个方法来搜索.EDCOX1 0中的Java文件，然后我把它们放在一个名为EDCOX1(6)的文件数组中，但是现在我正在努力迭代地把这个数组中的文件添加到我的新文件夹EDCOX1×1中。以下是迄今为止我所拥有的：

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import java.io.File;
import java.io.FileInputStream;
import java.io.FilenameFilter;
import java.util.ArrayList;

public class TwoFiles {

File dir;
File name;

public TwoFiles(File dirName, File fileName) {

dir = dirName;
name = fileName;

}

public void setDir(File m) {
this.dir = m;
}

public File getDir() {
return dir;
}

public void setNewFolder(File n) {
this.name = n;
}

public File getNewFolder() {
return name;
}

public File[] Finder(File dir) {

dir = getDir();

return dir.listFiles(new FilenameFilter() {

public boolean accept(File dir, String filename) {
return name.endsWith(".java"); }

} );
}

public static void main(String[] args) {

File folder = null;
File newFolder = null;
Integer b = null;

TwoFiles tf = new TwoFiles(folder, newFolder);

folder = tf.getDir();
newFolder = tf.getNewFolder();

File[] list = tf.Finder(folder); //add to an array

//here is where I've been experimenting to add files in `list` to new folder, `fileName`.

for (File file : list)
{
FileInputStream inFile = new FileInputStream(file);

while ((b = inFile.read()) != -1)
newFolder.write(b);
inFile.close();
}

//copy files from array (list) into newFolder

}

}

谢谢你的时间。

相关讨论

newfolder变量的类型为file。你不能写这个。我想，您的代码甚至不会编译。您必须在循环前面创建一个输出流：

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FileOutputStream fos = new FileOutputStream( newFolder);
try
{
for (File file : list)
{
FileInputStream inFile = new FileInputStream(file);

while ((b = inFile.read()) != -1)
fos.write(b);
inFile.close();
}
}
finally
{
fos.close();
}

您可以使用apache commons io copy directory()和iofilefilter(用于.java扩展名)将文件从一个目录复制到另一个目录。在此之前，您可以确保使用forcemkdir()为您的filename创建一个新目录。

这是我对你问题的看法：我创建了另一个构造函数，在这个构造函数中，您只能将想要连接的文件的路径放到目录/文件夹，以及连接结果的文件。

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public class TwoFiles {

private File dir;
private File name;

public TwoFiles(File dirName, File fileName) {
dir = dirName;
name = fileName;
}

public TwoFiles(String dirName, String destinationFileName) throws IOException{
dir=new File(dirName);
if(!dir.isDirectory()){
throw new FileNotFoundException();//here your exception in case when dirName is file name instead folder name
}
name=new File(destinationFileName);
if(!name.exists()){
name.createNewFile();
}
}

public void setDir(File m) {
this.dir = m;
}

public File getDir() {
return dir;
}

public void setNewFolder(File n) {
this.name = n;
}

public File getNewFolder() {
return name;
}

public void concatenateFiles() throws IOException{
File[] files=dir.listFiles();
for(File file: files){
if(file.getName().endsWith(".java")){ //check is right file
prescribe(name, file);
}
}
}

/** prescribe file to new destination */
private void prescribe(File destination, File file) throws IOException {
FileInputStream inFile = new FileInputStream(file);
FileOutputStream writer=new FileOutputStream(destination, true); //true means next file will be write beginning from end of the file
int x;
while((x=inFile.read())!=-1){
writer.write(x);
}
String test="
"; //next line in file
writer.write(test.getBytes());
writer.close();
inFile.close();
}

public static void main(String...strings){
String dirName="C/myApp/model/entity";
String fileName="C:/Users/Dell/Desktop/temp/test.java";
try {
new TwoFiles(dirName, fileName).concatenateFiles();

} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}

}