jQuery .prop() returns undefined, while .attr() works as expected for data-*
我只是想从两个元素中获取几个属性。从
时按预期工作
谁能解释我目睹的这种奇怪行为?
HTML
1 2 3 4 5 6 7 | <label for="firstName">First name</label> <button id="editFirstName" class="btn ctaBtn greenBtn editBtn">Edit</button> <button class="btn ctaBtn greenBtn saveBtn" data-detail="firstName">Save</button> <button id="closeFirstName" class="btn ctaBtn greyBtn closeBtn">Close</button> <input type="text" id="firstName" name="firstName" value="[+firstName+]" readonly> |
JS
1 2 3 4 5 6 7 8 9 | $(".saveBtn").on("click", function() { var saveBtn = $(this); // The following statement yields undefined. When using .attr() it works as expected. var detail = saveBtn.prop("data-detail"); var relevantInput = saveBtn.parent().next(); // The following statement works as expected. var value = relevantInput.prop("value"); // ... }); |
那是因为 HTML 元素上没有 data-detail 属性。
以下是 .data()、.prop() 和 .attr() 的简要说明:
DOM 元素是一个具有
考虑这个元素:
以下结果将是:
1 2 | $('input').prop('id'); // =>""-empty string, property id exist on the element (defined by DOM) , but is not set. $('input').attr('id');// => undefined - doesn't exist. |
如果您执行以下操作:
1 2 3 | $('input').attr('id',"someID"); $('input').prop('id'); // => "someID" $('input').attr('id'); // => "someID" |
还有:
1 2 3 | $('input').prop('id',"someOtherID"); $('input').prop('id');// => "someOtherID" $('input').attr('id');// => "someOtherID" |
So, some attributes and properties have 1:1 mapping. (change of
the attr result change of the prop and vice versa).
考虑以下内容:
1 2 3 | $('input').prop('value'); // => "someValue" $('input').val(); // => "someValue" $('input').attr('value'); // => "someValue" |
如果你这样做:
1 2 3 4 5 6 7 8 9 | $('input').prop('value','newVal'); // or $('input').val('newVal'); $('input').prop('value'); // =>"newVal" -value of the property $('input').val(); // =>"newVal" -value of the property $('input').attr('value'); // =>"someValue" -value of the attr didn't change, since in this case it is not 1:1 mapping (change of the prop value doesn't reflect to the attribute value). |
.data() 的情况
1) 获取方式:
- 请记住
1 | <input type="checkbox" data-detail="somedata"> |
1 2 3 4 5 6 | $('input')[0].dataset; //=> [object DOMStringMap] { detail:"somedata"} $('input')[0].dataset.detail; // =>"somedata" $('input').prop('dataset'); //=>[object DOMStringMap] { detail:"somedata"} $('input').prop('dataset').detail; // =>"somedata" $('input').data('detail'); // =>"somedata" $('input').attr('data-detail'); // =>"somedata" |
2) 设置方法:
I)
1 2 3 4 | $('input').prop('dataset'); //=> [object DOMStringMap] { detail:"newData"} $('input').prop('dataset').detail; // =>"newData" $('input').attr('data-detail'); // =>"newData" $('input').data('detail'); // =>"newData" |
II)
1 2 3 4 | $('input').prop('dataset'); //=> [object DOMStringMap] { detail:"newData"} $('input').prop('dataset').detail; // =>"newData" $('input').attr('data-detail'); // =>"newData" $('input').data('detail'); // =>"newData" |
So you can see that here is 1:1 mapping, attr change reflects prop and
vice versa.
但是检查第三种方式:
III)
1 2 3 4 | $('input').prop('dataset'); // => [object DOMStringMap] { detail:"somedata"} $('input').prop('dataset').detail; // =>"somedata" $('input').attr('data-detail'); // =>"somedata" $('input').data('detail'); // =>"newData" <-----****** |
那么,这里发生了什么?
$(elem).data(key, value) does not change theHTML5 data-* attributes
of the element. It stores its values in$.cache internally.
所以为了获得
1 2 3 4 5 6 7 | $(".saveBtn").on("click", function() { var saveBtn = $(this); var detail = saveBtn.data("detail"); var relevantInput = saveBtn.parent().next(); var value = relevantInput.prop("value"); }); |