关于python：如何无序排列变量列表的索引？

how do I shuffle the index of a variable list?

本问题已经有最佳答案，请猛点这里访问。

如何无序排列索引列表？使用此代码和变量列表

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17

#turns string to list
list=[]
#gets the sentence to count and what to count and deletes punctuation
punctuations = '''!()-[]{};:'"\,<>./?@#$%^&*_~'''
sentence=input("Enter sentence to count:")
sentence=sentence.lower()

no_punct =""
for char in sentence:
if char not in punctuations:
no_punct = no_punct + char

list=no_punct.split()

#this shows whether it is there or not
index=[index+1 for index,list in enumerate(list)]
print("the indices are",index)

相关讨论

以下代码对我有效。你随机洗牌有问题，但我让它在这里工作。记住，它不会返回任何内容，因此您必须先使用它，然后在洗牌后打印。

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23

import random

#turns string to list
list=[]
#gets the sentence to count and what to count and deletes punctuation
punctuations = '''!()-[]{};:'"\,<>./?@#$%^&*_~'''
sentence=input("Enter sentence to count:")
sentence=sentence.lower()

no_punct =""
for char in sentence:
if char not in punctuations:
no_punct = no_punct + char

list=no_punct.split()

#this shows whether it is there or not
index=[index+1 for index,list in enumerate(list)]
print("the indices are",index)

print(index)
random.shuffle(index)
print(index)

编辑：这可能会使它成为一个重复的问题，如评论中所提到的。