关于python：Traceback（最近一次调用最后一次）：错误


Traceback(most recent call last): error

本问题已经有最佳答案，请猛点这里访问。

我对python还不熟悉，我正在编写一个练习脚本，它生成一个介于1和20之间的随机数，要求您猜测该数字，直到正确为止，然后在正确之后打印猜测的数量。代码在我得到最后一个号码之前都有效，然后我得到这个错误：

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Traceback (most recent call last):
  File"C:\Users\James Brown\Desktop\guessnumber.py", line 20, in <module>
    guess()
  File"C:\Users\James Brown\Desktop\guessnumber.py", line 17, in guess
    guess()
  File"C:\Users\James Brown\Desktop\guessnumber.py", line 17, in guess
    guess()
  File"C:\Users\James Brown\Desktop\guessnumber.py", line 17, in guess
    guess()
  File"C:\Users\James Brown\Desktop\guessnumber.py", line 17, in guess
    guess()
  File"C:\Users\James Brown\Desktop\guessnumber.py", line 18, in guess
    print("Good job! You guessed my number in" + tries)
TypeError: Can't convert 'int' object to str implicitly

这是密码

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import random
number = random.randint(1,20)
tries = 0

print ("I am thinking of a number between 1 and 20")

def guess():
    print (number)
    global tries
    myGuess = int(input("Take a guess."))
    while (myGuess != number):
        if (myGuess > number):
            print ("Your guess is too high.")
        else:
            print ("Your guess is too low.")
        tries = tries+1
        guess()
    print("Good job! You guessed my number in" + tries)

guess()

号

有人能解释发生了什么以及如何防止这种情况发生吗？谢谢！

相关讨论

您需要将int转换为字符串，可以使用str()函数进行转换。

失败的原因是因为python不知道如何向文本中添加数字，所以如果您告诉python给您数字的文本版本，那么您可以将它加入到文本中。

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import random
number = random.randint(1,20)
tries = 0

print ("I am thinking of a number between 1 and 20")

def guess():
    print (number)
    global tries
    myGuess = int(input("Take a guess."))
    while (myGuess != number):
        if (myGuess > number):
            print ("Your guess is too high.")
        else:
            print ("Your guess is too low.")
        tries = tries+1
        guess()
    print("Good job! You guessed my number in" + str(tries))

guess()

号

您需要将您的int tries转换为字符串：

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str(tries)

新代码：

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import random
number = random.randint(1,20)
tries = 0

print ("I am thinking of a number between 1 and 20")

def guess():
    print (number)
    global tries
    myGuess = int(input("Take a guess."))
    while (myGuess != number):
        if (myGuess > number):
            print ("Your guess is too high.")
        else:
            print ("Your guess is too low.")
        tries = tries+1
        guess()
    print("Good job! You guessed my number in" + str(tries))

guess()

号

编辑正如评论中所提到的，这也是可行的。print函数将转换为隐式函数。

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print("Good job! You guessed my number in" , tries)
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