Python函数，它有两个值


Python function that takes two values

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这个函数取两个整数，x是小时，y是分钟。函数应将文本中的时间打印到最近的小时。这是我写的代码。

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def approxTime(x, y):
    if int(y) <= 24:
        print("the time is about quarter past" + int(y))
    elif 25 >= int(y) <=40:
        print("the time is about half past" + int(y))
    elif 41 >= int(y) <= 54:
        print("the time is about quarter past" + int(y+1))
    else:
        print("the time is about" + int(y+1) +"o'clock")
approxTime(3, 18)

但是，我收到了这个错误消息。

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  Traceback (most recent call last):   File
 "C:/Users/Jafar/Documents/approxTime.py", line 14, in <module>
      approxTime(3, 18)   File"C:/Users/Jafar/Documents/approxTime.py", line 5, in approxTime
      print("the time is about quarter past" + int(y)) TypeError: Can't convert 'int' object to str implicitly

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相关讨论

您正在尝试连接字符串和整数对象！将对象y或y+1转换为字符串，然后追加。像：

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print("the time is about quarter past" + str(y)) #similarly str(int(y)+1)
相关讨论

你得铸成一根绳子。您试图将int和字符串连接在一起，这是不兼容的。

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def approxTime(x, y):
     if int(y) <= 24:
         print("the time is about quarter past" + str(y))
     elif 25 >= int(y) <=40:
         print("the time is about half past" + str(y))
     elif 41 >= int(y) <= 54:
         print("the time is about quarter past" + str(y+1))
     else:
         print("the time is about" + str(y+1) +"o'clock")
approxTime(3, 18)

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