禁用外键约束，仍然不能截断表？ (SQL Server 2005)

Disabling foreign key constraint, still can't truncate table? (SQL Server 2005)

我有一个名为PX_Child的表，它在PX_Parent上有一个外键。我想暂时禁用此FK约束，以便我可以截断PX_Parent。我不确定这是怎么回事。

我试过这些命令

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ALTER TABLE PX_Child NOCHECK CONSTRAINT ALL

ALTER TABLE PX_Parent NOCHECK CONSTRAINT ALL

(truncate commands)

ALTER TABLE PX_Child CHECK CONSTRAINT ALL

ALTER TABLE PX_Parent CHECK CONSTRAINT ALL

但截断仍然告诉我，由于外键约束，它不能截断PX_Parent。我在网上看了一遍，似乎找不到我做错了什么，对不起这个问题的基本性质。

相关讨论

如果有任何外键引用它，则不能截断表，包括禁用的约束。您需要删除外键约束或使用DELETE命令。

相关讨论

有一种更容易的方式。我遇到了同样的问题并找到了这个解决方案：
https://www.mssqltips.com/sqlservertip/3347/drop-and-recreate-all-foreign-key-constraints-in-sql-server/

如果您只是在数据库中运行此查询，它将生成您需要在您的sproc之前/之后包含的T-SQL，以便删除然后恢复任何外键约束。

不要担心尝试理解这个查询本身。

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CREATE TABLE #x -- feel free to use a permanent table
(
drop_script NVARCHAR(MAX),
create_script NVARCHAR(MAX)
);

DECLARE @drop NVARCHAR(MAX) = N'',
@create NVARCHAR(MAX) = N'';

-- drop is easy, just build a simple concatenated list from sys.foreign_keys:
SELECT @drop += N'
ALTER TABLE ' + QUOTENAME(cs.name) + '.' + QUOTENAME(ct.name)
+ ' DROP CONSTRAINT ' + QUOTENAME(fk.name) + ';'
FROM sys.foreign_keys AS fk
INNER JOIN sys.tables AS ct
ON fk.parent_object_id = ct.[object_id]
INNER JOIN sys.schemas AS cs
ON ct.[schema_id] = cs.[schema_id];

INSERT #x(drop_script) SELECT @drop;

-- create is a little more complex. We need to generate the list of
-- columns on both sides of the constraint, even though in most cases
-- there is only one column.
SELECT @create += N'
ALTER TABLE '
+ QUOTENAME(cs.name) + '.' + QUOTENAME(ct.name)
+ ' ADD CONSTRAINT ' + QUOTENAME(fk.name)
+ ' FOREIGN KEY (' + STUFF((SELECT ',' + QUOTENAME(c.name)
-- get all the columns in the constraint table
FROM sys.columns AS c
INNER JOIN sys.foreign_key_columns AS fkc
ON fkc.parent_column_id = c.column_id
AND fkc.parent_object_id = c.[object_id]
WHERE fkc.constraint_object_id = fk.[object_id]
ORDER BY fkc.constraint_column_id
FOR XML PATH(N''), TYPE).value(N'.[1]', N'nvarchar(max)'), 1, 1, N'')
+ ') REFERENCES ' + QUOTENAME(rs.name) + '.' + QUOTENAME(rt.name)
+ '(' + STUFF((SELECT ',' + QUOTENAME(c.name)
-- get all the referenced columns
FROM sys.columns AS c
INNER JOIN sys.foreign_key_columns AS fkc
ON fkc.referenced_column_id = c.column_id
AND fkc.referenced_object_id = c.[object_id]
WHERE fkc.constraint_object_id = fk.[object_id]
ORDER BY fkc.constraint_column_id
FOR XML PATH(N''), TYPE).value(N'.[1]', N'nvarchar(max)'), 1, 1, N'') + ');'
FROM sys.foreign_keys AS fk
INNER JOIN sys.tables AS rt -- referenced table
ON fk.referenced_object_id = rt.[object_id]
INNER JOIN sys.schemas AS rs
ON rt.[schema_id] = rs.[schema_id]
INNER JOIN sys.tables AS ct -- constraint table
ON fk.parent_object_id = ct.[object_id]
INNER JOIN sys.schemas AS cs
ON ct.[schema_id] = cs.[schema_id]
WHERE rt.is_ms_shipped = 0 AND ct.is_ms_shipped = 0;

UPDATE #x SET create_script = @create;

PRINT @drop;
PRINT @create;

/*
EXEC sp_executesql @drop
-- clear out data etc. here
EXEC sp_executesql @create;
*/

生成一堆：

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ALTER TABLE [dbo].[Whatever] DROP CONSTRAINT....
--
ALTER TABLE [dbo].[Whatever] ADD CONSTRAINT....

相关讨论

SQL服务器不允许您在约束存在时截断表，即使它已被禁用。
删除约束并在截断表后重新创建约束。
或者只需删除并重新创建表格，无论哪种更容易在您的应用程序中执行。

相关讨论

在外键约束时没有这样的选项来截断表，但是我们可以使用一些技巧

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ALTER TABLE [dbo].[table2] DROP CONSTRAINT [FK_table2_table1]
GO
truncate table [table1]
GO
ALTER TABLE [dbo].[table2] WITH CHECK ADD CONSTRAINT [FK_table2_table1] FOREIGN KEY([FKId])
REFERENCES [dbo].[table1] ([ID])
GO

ALTER TABLE [dbo].[table2] CHECK CONSTRAINT [FK_table2_table1]
GO