关于python：当除以0时，我希望它打印给定的文本

When didving by 0, I want it to print given text

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import math

def roots4(outfile,a,b,c):
"""Prints the solutions of 'x' for equation ax2 + bx + c = 0"""
d = b * b - 4 * a * c
if a == 0 and b == 0 and c == 0:
print"X = All complex/real numbers."

if c != 0:
print"X = No real solutions."

e = (-c / (b))
if a == 0 and b > 0 < c:
print"There's only one solution:" + e

solutions = [str(-b / (2 * a))]
if a != 0 and d == 0:
print"There's only one solution:" + solutions

solutions2 = [str((-b + math.sqrt(d)) / 2.0 / a), str((-b - math.sqrt(d)) / 2.0 / a)]
if a != 0 and d > 0:
print"There's two solutions:" + solutions2

xre = str((-b) / (2 * a))
xim = str((math.sqrt(-d)) / (2 * a))
solutions3 = [xre +" +" + xim +"i", xre +" -" + xim +"i"]
if a != 0 and d < 0:
print"Solutions are:" + solutions3

我得到一个"ZeroDivisionError：float division by zero"错误，因为当输入文件中"b"为"0"时，我除以零。如何绕过错误以便打印所需的文本？满足"if"条件时，我想要的输出需要是所需的打印语句。

其中(a，b，c)

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0.0, 0.0, 0.0

0.0, 0.0, 1.0

0.0, 2.0, 4.0

1.0, 2.0, 1.0

1.0, -5.0, 6.0

1.0, 2.0, 3.0

相关讨论

你为什么做这个？你能想到更好的显示文字的方法吗？你怎么不分零呢？尝试显示结果，而不是除以除以不除以零。

我不知道Python。但要知道这个概念。

所以请纠正Python代码错误。

打印ax2 + bx + c = 0的解

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def roots4(outfile,a,b,c):
d = (b * b) - (4 * a * c)

if a == 0 and b == 0 and c==0:
print"This is not quadratic equations"
if a == 0 and b == 0:
print"Invalid equations"
if a == 0:
e = [str(-b / (2 * a))]
print"There's only one solution: X=" + e
if d == 0 :
solutions = -b / (2 * a)
print"Two roots are same X =" + solutions
if d > 0:
solutions2 = [str((-b + math.sqrt(d)) / (2.0 * a)), str((-b - math.sqrt(d)) / (2.0 * a))]
print"There's two solutions:" + solutions2
if d < 0:
xre = str((-b) / (2 * a))
xim = str((math.sqrt(-d)) / (2 * a))
solutions3 = [xre +" +" + xim +"i", xre +" -" + xim +"i"]
print"Solutions are:" + solutions3