ELIF，ELSE语法错误python 3.2.1


ELIF, ELSE syntax error python 3.2.1

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def magic_n(guess2): #Function, have someone guess if number is 7, max 5 tries
magicn2 == 7
tries = 0
while (tries < 5) and (guess2 != magicn2):
 if guess < 7 :
    tries = tries + 1
    print("Too Low")
    guess2 = int(input("Give me another number since the last one was too high :"))
    elif guess > 7:
    tries = tries + 1
    print("Too high")
    guess2 = int(input("Give me another number since the l ast one was too low :")
    else :
    print("Good job you got it")

guess2 = int(输入("请给我一个号码：")
打印(magic_n(guess2)

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相关讨论

是缩进....

当你使用python时......我建议你看看PYCHARM，因为你可以避免将来出现这样的错误。 我经常使用它并自动格式化。

https://www.jetbrains.com/pycharm/

标识不正确，在"else"之前需要再加一个括号。

所以它会是：

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def magic_n(guess2):
    magicn = 7
    tries = 0
    while (tries < 5) and (guess2 != magicn):
        if guess2 < 7:
            tries += 1
            print("Too Low")
            guess2 = int(input("Give me another number since the last one was too high :"))
        elif guess2 > 7:
            tries += 1
            print("Too high")
            guess2 = int(input("Give me another number since the l ast one was too low :"))
        else:
            print("Good job you got it")

第12行：

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guess2 = int(input("Give me another number since the l ast one was too low :")) //bracket missing

缩进必须在python中是正确的。在python中没有}所以代码片段需要了解我的块在哪里开始以及它在哪里结束
所以

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if condition:
   ........
   ........
elif condition :
   ........
   ........
else :
   ........