关于xml：AES 256 32字节密钥加密/解密Java

AES 256 32 bytes key Encrypt/Decrypt Java

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我需要使用带有32字节密钥的AES 256来加密XML消息(它以字符串形式出现)。我尝试了以下(来自http://aesencryption.net/)：

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import java.io.UnsupportedEncodingException;
import java.security.MessageDigest;
import java.security.NoSuchAlgorithmException;
import java.util.Arrays;
import javax.crypto.Cipher;
import javax.crypto.spec.SecretKeySpec;
import org.apache.commons.codec.binary.Base64;
/**
Aes encryption
*/
public class AES
{

private static SecretKeySpec secretKey ;
private static byte[] key ;

private static String decryptedString;
private static String encryptedString;

public static void setKey(String myKey){

MessageDigest sha = null;
try {
key = myKey.getBytes("UTF-8");
System.out.println(key.length);
sha = MessageDigest.getInstance("SHA-1");
key = sha.digest(key);
key = Arrays.copyOf(key, 16); // use only first 128 bit
System.out.println(key.length);
System.out.println(new String(key,"UTF-8"));
secretKey = new SecretKeySpec(key,"AES");

} catch (NoSuchAlgorithmException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (UnsupportedEncodingException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}

}

public static String getDecryptedString() {
return decryptedString;
}
public static void setDecryptedString(String decryptedString) {
AES.decryptedString = decryptedString;
}
public static String getEncryptedString() {
return encryptedString;
}
public static void setEncryptedString(String encryptedString) {
AES.encryptedString = encryptedString;
}
public static String encrypt(String strToEncrypt)
{
try
{
Cipher cipher = Cipher.getInstance("AES/ECB/PKCS5Padding");

cipher.init(Cipher.ENCRYPT_MODE, secretKey);

setEncryptedString(Base64.encodeBase64String(cipher.doFinal(strToEncrypt.getBytes("UTF-8"))));

}
catch (Exception e)
{

System.out.println("Error while encrypting:"+e.toString());
}
return null;
}
public static String decrypt(String strToDecrypt)
{
try
{
Cipher cipher = Cipher.getInstance("AES/ECB/PKCS5PADDING");

cipher.init(Cipher.DECRYPT_MODE, secretKey);
setDecryptedString(new String(cipher.doFinal(Base64.decodeBase64(strToDecrypt))));

}
catch (Exception e)
{

System.out.println("Error while decrypting:"+e.toString());
}
return null;
}
public static void main(String args[])
{
final String strToEncrypt ="My text to encrypt";
final String strPssword ="C0BAE23DF8B51807B3E17D21925FADF273A70181E1D81B8EDE6C76A5C1F1716E";
AES.setKey(strPssword);

AES.encrypt(strToEncrypt.trim());

System.out.println("String to Encrypt:" + strToEncrypt);
System.out.println("Encrypted:" + AES.getEncryptedString());

final String strToDecrypt = AES.getEncryptedString();
AES.decrypt(strToDecrypt.trim());

System.out.println("String To Decrypt :" + strToDecrypt);
System.out.println("Decrypted :" + AES.getDecryptedString());

}

}

我试图将键数组长度从16更改为32并使用更大的输入字符串
(我认为这是32个长度的关键)但这不起作用。

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key = Arrays.copyOf(key, 32);

要加密的消息将如下所示：

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<Estructure>
<General>GENERAL DATA</General>
</Estructure>
<Datos>
<DATE>20140606</DATE>
</Datos>

当我运行时，我得到以下异常：

Error while encrypting: java.security.InvalidKeyException: Illegal key size or default parameters

使用16字节长度键时，它可以正常工作。如何使用32个字节？