关于python：如何获取Flask中的当前基本URL？

How can I get current base URI in flask?

本问题已经有最佳答案，请猛点这里访问。

在下面的代码中，我想将URL存储在变量中以检查发生URL错误的错误。

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@app.route('/flights', methods=['GET'])
def get_flight():
flight_data= mongo.db.flight_details
info = []
for index in flight_data.find():
info.append({'flight_name': index['flight_name'], 'flight_no': index['flight_no'], 'total_seat': index['total_seat'] })
if request.headers['Accept'] == 'application/xml':
template = render_template('data.xml', info=info)
xml_response = make_response(template)
xml_response.headers['Accept'] = 'application/xml'
logger.info('sucessful got data')
return xml_response
elif request.headers['Accept'] == 'application/json':
logger.info('sucessful got data')
return jsonify(info)

输出：

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* Restarting with stat
* Debugger is active!
* Debugger PIN: 165-678-508
* Running on http://127.0.0.1:5000/ (Press CTRL+C to quit)
127.0.0.1 - - [28/Mar/2017 10:44:53]"GET /flights HTTP/1.1" 200 -

我要此消息

1	"127.0.0.1 - - [28/Mar/2017 10:44:53]"GET /flights HTTP/1.1" 200 -"

应该存储在变量中，或者如何获取正在执行的当前URL？

您可以在烧瓶的request函数上使用base_url方法。

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from flask import Flask, request

app = Flask(__name__)

@app.route('/foo')
def index():
return request.base_url

if __name__ == '__main__':
app.run()

如果应用程序路由为/foo，则返回以下内容：

1	http://localhost:5000/foo