关于python：PyQt4-＆gt; PyQt5翻译

PyQt4->PyQt5 translation

我对表数据的分页显示很感兴趣。我找到了这个链接：https://sateshkumarb.wordpress.com/2012/04/01/paginated-display-of-table-data-in-pyqt/用Pyqt4编写的有趣代码。我试图用pyqt5在python 3.4上翻译它。代码如下：

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import sys
from PyQt5 import QtWidgets, QtCore

class Person(object):
"""Name of the person along with his city"""
def __init__(self,name,city):
self.name = name
self.city = city
class PersonDisplay(QtWidgets.QMainWindow):
def __init__(self, parent=None):
super(PersonDisplay, self).__init__(parent)
#QtWidgets.QMainWindow.__init__(self, parent)
self.setWindowTitle('Person City')
view = QtWidgets.QTableView()
tableData = PersonTableModel()
view.setModel(tableData)
self.setCentralWidget(view)
tableData.addPerson(Person('Ramesh', 'Delhi'))
tableData.addPerson(Person('Suresh', 'Chennai'))
tableData.addPerson(Person('Kiran', 'Bangalore'))

class PersonTableModel(QtCore.QAbstractTableModel):
def __init__(self):
super(PersonTableModel,self).__init__()
self.headers = ['Name','City']
self.persons = ['Ramesh', 'Delhi']

def rowCount(self,index=QtCore.QModelIndex()):
return len(self.persons)

def addPerson(self,person):
self.beginResetModel()
self.persons.append(person)
self.endResetModel()

def columnCount(self,index=QtCore.QModelIndex()):
return len(self.headers)

def data(self,index,role=QtCore.Qt.DisplayRole):
col = index.column()
person = self.persons[index.row()]
if role == QtCore.Qt.DisplayRole:
if col == 0:
return QtWidgets.QVariant(person.name)
elif col == 1:
return QtWidgets.QVariant(person.city)
return QtWidgets.QVariant()

def headerData(self,section,orientation,role=QtCore.Qt.DisplayRole):
if role != QtCore.Qt.DisplayRole:
return QtWidgets.QVariant()

if orientation == QtCore.Qt.Horizontal:
return QtWidgets.QVariant(self.headers[section])
return QtWidgets.QVariant(int(section + 1))

if __name__ == '__main__':
app = QtWidgets.QApplication(sys.argv)
appWin = PersonDisplay()
appWin.show()
sys.exit(app.exec_())

看起来是正确的，但运行停止在：view.setmodel(tabledata)。我不知道这是因为我的翻译还是代码错误。知道吗？谢谢

1)是在QtWidgets.QVariant筹集AttributeErrorQVariant是因为在QtCoreQtWidgets包装困难。

2)在pyqt5你不需要使用明确的QVariant，所以你可以完全删除它们。

3)在PersonTableModel.data()person是一个字符串，和person.nameperson.city想和高层的错误。

在一个固定的版本的PersonTableModel：

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class PersonTableModel(QtCore.QAbstractTableModel):
def __init__(self):
super(PersonTableModel,self).__init__()
self.headers = ['Name','City']
self.persons = ['Ramesh', 'Delhi']

def rowCount(self,index=QtCore.QModelIndex()):
return len(self.persons)

def addPerson(self,person):
self.beginResetModel()
self.persons.append(person)
self.endResetModel()

def columnCount(self,index=QtCore.QModelIndex()):
return len(self.headers)

def data(self,index,role=QtCore.Qt.DisplayRole):
col = index.column()
person = self.persons[index.row()]
if role == QtCore.Qt.DisplayRole:
if col == 0:
return person
elif col == 1:
return person
return None

def headerData(self,section,orientation,role=QtCore.Qt.DisplayRole):
if role != QtCore.Qt.DisplayRole:
return None

if orientation == QtCore.Qt.Horizontal:
return self.headers[section]
return int(section + 1)

备注

异常：这是提高您的代码

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Traceback (most recent call last):
File"test.py", line 51, in headerData
return QtWidgets.QVariant()
AttributeError: module 'PyQt5.QtWidgets' has no attribute 'QVariant'

它可以包括在已经是这样的问题。