关于python：使用列表推导过滤字符串列表

Filter list of strings using list comprehension

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>>> li = ["a b self","mpilgrim","foo c","b","c","b","d","d"]
>>> condition = ["b","c","d"]
>>> [elem for elem in li if elem in condition]
['b', 'c', 'b', 'd', 'd']

但是有返回的方法吗

1	['a b self','foo c','b', 'c', 'b', 'd', 'd']

号

由于b和c包含在'a b self'和'foo c'中，所以我希望代码也返回这两个值。

相关讨论

假设代码需要检索包含任何条件字符串的所有字符串：

1	[elem for elem in li if any(c in elem for c in condition)]

如果需要完全匹配某个条件：

1 2	[elem for elem in li if any(re.search('(^\|\s){}(\s\|$)'.format(c), elem) for c in condition)]

号

编辑：这可以简化为一个预先定义的regex：

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predicate = re.compile('(^|\s)({})(\s|$)'.format('|'.join(condition)))

[elem for elem in li if predicate.search(elem)]