关于python：为什么说粗体是无效的语法？

Why is it saying that the = in bold is an invalid syntax?

本问题已经有最佳答案，请猛点这里访问。

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print('Select operation')
print('Choose from:')
print('+')
print('-')
print('*')
print('/')

choice=input('Enter choice (+,-,*,/):')

num1=int(input('Enter first number:'))
num2=int(input('Enter second number:'))

if choice== '+':
print(num1,'+',num1,'=', (num1+num2))
while restart **=** input('Do you want to restart the calculator y/n'):
if restart == 'y':t
print('restart')
else restart == 'n':
print('Thanks for using my program')
break

elif choice== '-':
print(num1,'-',num2,'=', (num1-num2))

elif choice== '*':
print(num1,'*',num2,'=', (num1*num2))

elif choice== '/':
print(num1,'/',num2,'=',(num1/num2))

else:
print('Invalid input')

=粗体有什么问题？我不明白它有什么问题？有人请回答我的问题。

谢谢，
夏洛特

相关讨论

这里有多个问题：

无法在while循环中检查从input到变量的赋值，您应该将其拆分为赋值和检查。

else不能包含条件

你也有打印结果的错误 - 你打印num1两次

缩进在Python中很有意义 - 请确保下次正确缩进

修复上述问题：

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def calc():
print('Select operation')
print('Choose from:')
print('+')
print('-')
print('*')
print('/')

choice=input('Enter choice (+,-,*,/):')

num1=int(input('Enter first number:'))
num2=int(input('Enter second number:'))
if choice == '+':
print("{}+{}={}".format(num1, num2, num1+num2))

elif choice == '-':
print("{}-{}={}".format(num1, num2, num1-num2))

elif choice == '*':
print("{}*{}={}".format(num1, num2, num1*num2))

elif choice == '/':
print("{}/{}={}".format(num1, num2, num1/num2))
else:
print('Invalid input')

if __name__ == '__main__':
restart = 'y'
while restart:
if restart == 'y':
print('restart')
calc()
restart = input('Do you want to restart the calculator y/n')
elif restart == 'n':
print('Thanks for using my program')
break