Python连接到MySQL错误

Python connect to MySQL error

当我想将python与mysql连接时，为什么我总是得到这个错误TypeError: __init__() takes 1 positional argument but 2 were given？

准确的错误代码是：

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Traceback (most recent call last):
File"cone.py", line 4, in
conn = mysql.connector.connect(f)
File"C:\Python34\lib\site-packages\mysql\connector\__init__.py", line 179, in connect
return MySQLConnection(*args, **kwargs)
File"C:\Python34\lib\site-packages\mysql\connector\connection.py", line 57, in __init__
super(MySQLConnection, self).__init__(*args, **kwargs)
TypeError: __init__() takes 1 positional argument but 2 were given

以下是我的代码：

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import mysql.connector

f="localhost","username","password","db"
conn = mysql.connector.connect(f)

c= conn.cursor()

c.execute("SELECT * FROM test")

rows=c.fetchall()

for eachRow in rows:
print (eachRow)

相关讨论

如果您已经成功修复了mysqldb，那么您可以这样连接

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import MySQLdb

mydb = MySQLdb.connect(host = 'localhost',user = 'flo',passwd = '********',db = 'yourdb')
cur = mydb.cursor()
command = cur.execute('SELECT * FROM yourtable')
results = cur.fetchall()

print (results)

在python3.4中，使用pymysql尝试相同的方法，

安装EDOCX1[0]

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import pymysql
conn = pymysql.connect("localhost","dev","pwd","db_name")
cur = conn.cursor()

在mysql.connector.connect中应该这样连接

1	conn = mysql.connector.connect(host="localhost",user="uname", password="mypwd", database="emp_db")

例如，

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>>> conn = mysql.connector.connect(f)Traceback (most recent call last):
File"<stdin>", line 1, in <module>
File"/usr/lib/python2.7/dist-packages/mysql/connector/__init__.py", line 98, in connect
return MySQLConnection(*args, **kwargs)
TypeError: __init__() takes exactly 1 argument (2 given)
>>> conn = mysql.connector.connect(host="localhost",user="uname", password="pwd", database="reposter$tutorial_database")
>>>

这是DOC