declaring a startdate & endate using joda time?
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我已经导入了joda libary,并且可以导入Easy Reader类。但是,我需要正确的格式设置帮助,这样我可以计算介于和之间的天数,是的,我对mm/dd/yyyy是水化的,但是我使用了整数。我还需要进口其他东西吗?我在佐达是个新手,所以请耐心点,谢谢。一切似乎都很顺利,但我找不到正确的语法来帮助我找出两个日期之间的区别,我也找不到。
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 | import org.joda.time.DateTime; import org.joda.time.DateTimeZone; import org.joda.time.LocalDate; class starter{ public static void BdayPrgm(String args[]){ System.out.println("Please Enter Today's Month:"); EasyReader month = new EasyReader(); //this will indentify it as an INT, not a string. //quest is a question btw. todaysmon = month.readInt(); System.out.println("What number is today?:"); EasyReader currentday = new EasyReader(); todayday = currentday.readInt(); System.out.println("What is today's year?:"); EasyReader todayyear = new EasyReader(); year = todayyear.readInt(); System.out.println(""); System.out.println("What is your BdayMonth?:"); EasyReader thatyear = new EasyReader(); bdaymon = thatyear.readInt(); System.out.println("What is your Bday #?:"); EasyReader thatday = new EasyReader(); thatgr8day = thatday.readInt(); System.out.println("What is the bdayyear?:"); EasyReader bdayyear = new EasyReader(); bdayyr = bdayyear.readInt(); int age; age = year - bdayyr; //we can get start date by putting test maybe? DateTimeZone LA = DateTimeZone.forID("America/Los_Angeles"); LocalDate start = new LocalDate(year,todaysmon,todayday); LocalDate end = new LocalDate(year,bdaymon,thatgr8day); int Days; //code isn't compileing below. I don't know what I'm doing wrong. Days.daysBetween(new LocalDate(start),new LocalDate(end)).getDays(); //int days = d.getdays; System.out.println(""); System.out.println(CELEB1+" is going to be"+age+" years old in X days!"); |
}
1 | } |
这个
1 2 | int Days; Days.daysBetween(new LocalDate(start),new LocalDate(end)).getDays(); |
应该是这样的
1 | int dayCount = Days.daysBetween(start, end).getDays(); |
因为
1 | import org.joda.time.Days; |