关于python：一个多级嵌套列表

A multi level nested list

我正在尝试实现一个定制的自动机，其中转换表如下所示：

enter image description here

该表是动态的，即每个单元格的列标题、行名称和数据都可以在运行时确定。列名和行名也是必需的。

我试过这个密码

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table = []
table.append(["A",[0,["B",2],["C1",2]],[1,["C1",1]]])
table.append(["B",[0,["C",1]],[1,["C2",1]]])
table.append(["C",[0,["C1",1]],[1,["C2",1]]])

但我无法访问单元中的单个项目，即B或B:2等中的2个项目，然后我尝试

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row = ["A","B","C","C1","C2"]
col = [0,1]
table = []
table.append([[["B",2],["C1",2]],["C1",1]])
table.append([["C",1],["C2",1]])
table.append([["C1",1],["C2",1]])

print(table[0][0][0][0])

现在，我可以访问单个项目(在上面的例子中是b)，但是我丢失了四个下标。特别是当我事先不知道清单的深度时。需要一些帮助才能以某种简单的方式完成。作为一个新手，我会感谢一些对Python密码的解释。

更新：这是非确定性有限自动机。我试过自动化软件包，但它们没有解决我的问题。根据Tadhg McDonald Jensen的解决方案，它给出了表中第一行(a)的正确输出，但第二行(b)的错误消息。这是密码

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table = {}
table["A"] = {0: {"B":2,"C1":2}, 1: {"C1":1}}
table["B"] = {0: {"C":1}, 1: {"C2",1}}
table["C"] = {0: {"C1":1}, 1: {"C2",1}}

for key,value in table["A"][0].items(): \\ok treated as dictionary (1)
print(key, value, sep="\t")
for key,value in table["A"][1].items(): \\ok treated as dictionary (2)
print(key, value, sep="\t")
for key,value in table["B"][0].items(): \\ok treated as dictionary (3)
print(key, value, sep="\t")
for key,value in table["B"][1].items(): \\wrong: why treated as set? Although same as (2)
print(key, value, sep="\t") \\Error message: AttributeError: 'set' object has no attribute 'items'

输出是

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B 2
C1 2
C1 1
C 1
Traceback (most recent call last):
File"C:/Users/Abrar/Google Drive/Tourism Project/Python Projects/nestedLists.py", line 17, in <module>
for key,value in table["B"][1].items():
AttributeError: 'set' object has no attribute 'items'