Python scheduling a job starting every weekday and running every hour
我目前有一个示例代码定义为:
1 2 3 4 5 6 7 8 9 10 11 12 | import schedule import time def job(t): print ("I'm working...", t) return schedule.every().day.at("01:00").do(job,'It is 01:00') while True: schedule.run_pending() time.sleep(60) # wait one minute |
我希望在工作日的上午9点到下午4点每小时运行代码。 即我希望星期一至星期五的每天上午9点,上午10点,...,下午3点,下午4点运行代码。
阅读
此外,以下
1 2 3 4 5 6 7 8 9 10 11 | def weekday_job(x, t=None): week = datetime.today().weekday() if t is not None and week < 5: schedule.every().day.at(t).do(x) weekday_job(main, '01:00') weekday_job(main, '02:00') while True: schedule.run_pending() time.sleep(60) |
它对我有用的唯一方法是:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 | import schedule import datetime import time nowtime = str(datetime.datetime.now()) def job(t): print("I'm working...", str(datetime.datetime.now()), t) for i in ["06:00","09:00","12:00","15:00","18:00"]: schedule.every().monday.at(i).do(job, i) schedule.every().tuesday.at(i).do(job, i) schedule.every().wednesday.at(i).do(job, i) schedule.every().thursday.at(i).do(job, i) schedule.every().friday.at(i).do(job, i) while True: schedule.run_pending() time.sleep(30) |