关于python：urllib不能使用api请求


urllib not working with api request

即时通讯尝试编写此代码，我从openweathermap.org请求此信息thourgh api并尝试打印当前时间的温度和位置。

大多数代码都是我在互联网上找到的一些技巧。

现在我收到了这个错误并且卡住了。 谁能帮助我再次走上正确的道路？

继承我的代码：

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import urllib.request, urllib.parse, urllib.error
import json

while True:
    zipcode = input('Enter zipcode: ')
    if len(zipcode) < 1: break

    url = 'http://api.openweathermap.org/data/2.5/weather?
zip='+zipcode+',nl&appid=db071ece9a338a36e9d7a660ec4f0e37?'

    print('Retrieving', url)
    uh = urllib.request.urlopen(url)
    data = uh.read().decode()
    print('Retrieved', len(data), 'characters')

    try:
        js = json.loads(data)
    except:
        js = None

    temp = js["main"]["temp"]
    loc = js["name"]

    print("temperatuur:", temp)
    print("locatie:", loc)

所以网址是这样的：http：//api.openweathermap.org/data/2.5/weather？zip = 3032，nl＆appid = db071ece9a338a36e9d7a660ec4f0e37

我得到的错误是：

Enter zipcode: 3343
Retrieving http://api.openweathermap.org/data/2.5/weather?zip=3343,nl&appid=db071ece9a338a36e9d7a660ec4f0e37?
Traceback (most recent call last):
File"weatherapi2.py", line 12, in
uh = urllib.request.urlopen(url)
File"C:\Users\ErfanNariman\AppData\Local\Programs\Python\Python36\lib\urllib
equest.py", line 223, in urlopen
return opener.open(url, data, timeout)
File"C:\Users\ErfanNariman\AppData\Local\Programs\Python\Python36\lib\urllib
equest.py", line 532, in open
response = meth(req, response)
File"C:\Users\ErfanNariman\AppData\Local\Programs\Python\Python36\lib\urllib
equest.py", line 642, in http_response
'http', request, response, code, msg, hdrs)
File"C:\Users\ErfanNariman\AppData\Local\Programs\Python\Python36\lib\urllib
equest.py", line 570, in error
return self._call_chain(*args)
File"C:\Users\ErfanNariman\AppData\Local\Programs\Python\Python36\lib\urllib
equest.py", line 504, in _call_chain
result = func(*args)
File"C:\Users\ErfanNariman\AppData\Local\Programs\Python\Python36\lib\urllib
equest.py", line 650, in http_error_default
raise HTTPError(req.full_url, code, msg, hdrs, fp)
urllib.error.HTTPError: HTTP Error 401: Unauthorized

经过一些故障排除后我发现了你的问 你有一个额外的'？' 在你的python的url的末尾。

删除它，您的请求工作正常。 尝试使用此代码并使用 -

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import urllib.request, urllib.parse, urllib.error
import json

while True:
    zipcode = input('Enter zipcode: ')
    if len(zipcode) < 1: break

    url = 'http://api.openweathermap.org/data/2.5/weather?zip='+zipcode+',nl&appid=db071ece9a338a36e9d7a660ec4f0e37'

    print('Retrieving', url)
    uh = urllib.request.urlopen(url)
    data = uh.read().decode()
    print('Retrieved', len(data), 'characters')

    try:
        js = json.loads(data)
    except:
        js = None

    temp = js["main"]["temp"]
    loc = js["name"]

    print("temperatuur:", temp)
    print("locatie:", loc)