Get all characters of string except the last 2 in bash
我想知道如何打印我拥有的字符串，但没有bash中的最后两个字符。
例如：
1 | str ="hello.c" |
然后只打印
谢谢你的回答。
答案是使用bash-builtin字符串操作：
1 2 | str="hello.c" echo"${str%.c}" |
在线尝试！
引用文档：
${parameter%word}
${parameter%%word} The word is expanded to produce a pattern just as in filename
expansion. If the pattern matches a trailing portion of the expanded
value of parameter, then the result of the expansion is the value of
parameter with the shortest matching pattern (the '% ' case) or the
longest matching pattern (the '%% ' case) deleted. If parameter is '@ '
or '* ', the pattern removal operation is applied to each positional
parameter in turn, and the expansion is the resultant list. If
parameter is an array variable subscripted with '@ ' or '* ', the
pattern removal operation is applied to each member of the array in
turn, and the expansion is the resultant list.