关于算法：以天为单位计算用户的年龄

Calculate the user's age in days java

本问题已经有最佳答案，请猛点这里访问。

任务：需要计算用户的年龄，以天、小时、分钟为单位。输入出生日期和今天的日期。

似乎，年龄计算正确，但在几天内没有正确的数字。如何计算日与日之间的差额？

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106

import java.util.Scanner;

class Solution {

public static void main(String[] args) {

Scanner scanner = new Scanner(System.in);

int day;
int year;
int month;
int day2; //today
int year2; //today's year
int month2; //today's month
do {
System.out.print("Enter the year of birth:");
year = scanner.nextInt();
} while (year < 1000 || year > 2019);

do {
System.out.print("Enter the month of birth:");
month = scanner.nextInt();
} while (month < 1 || month > 12);

do {
System.out.print("Enter the day of birth:");
day = scanner.nextInt();
} while (day < 1 || day > 31);

do {
System.out.print("Enter today's year:");
year2 = scanner.nextInt();
} while (year2 < 1000 || year2 > 2019);

do {
System.out.print("Enter today's month:");
month2 = scanner.nextInt();
} while (month2 < 1 || month2 > 12);

do {
System.out.print("Enter today:");
day2 = scanner.nextInt();
} while (day2 < 1 || day2 > 31);

int year_leap;
int[] month_day = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};

if (year % 4 == 0 && year % 100 != 0 || year % 400 == 0) {
year_leap = 366;
month_day[1] = 29;
} else {
month_day[1] = 28;
year_leap = 365;
}

int userYear = 0;
int userMonth;
int userDay;

if (year <= year2) {
userYear = year2 - year;
} else System.out.printf("Error!!! %n");

if (month > month2) {
userYear--;
userMonth = month2 + 12 - month;
} else userMonth = month2 - month;

if (day > day2) {
userMonth--;
userDay = day2 + month_day[userMonth] - day;
} else userDay = day2 - day;

int day_year = 0;
int day_month = 0;
int day_age = 0;

while (year < year2 - 1) {

if (year % 4 == 0 && year % 100 != 0 || year % 400 == 0) {
year_leap = 366;
month_day[1] = 29;
} else {
year_leap = 365;
month_day[1] = 28;

}
year++;
day_year = day_year + year_leap;
}

day_month = month_day[1] * userMonth + userDay; // 31 days in a month
day_age = day_year + day_month;

System.out.printf("------------------------------------ %n");
System.out.println("Your age:" + userYear +"." + userMonth +"." + userDay);
System.out.println("Your in days:" + day_age);

}
}

在python上找到了必要的算法。告诉我如何在Java中实现它？

1
2
3
4
5
6
7
8
9
10
11
12

def dateIsBefore(year1, month1, day1, year2, month2, day2):
return (year1, month1, day1) < (year2, month2, day2)

def daysBetweenDates(year1, month1, day1, year2, month2, day2):
assert not dateIsBefore(year2, month2, day2, year1, month1, day1)
days = 0
while dateIsBefore(year1, month1, day1, year2, month2, day2):
days += 1
year1, month1, day1 = nextDay(year1, month1, day1)
return days