How to Stop a for loop, inside of a while Loop in python
我正在制作一个简单的运动员比赛时间数据输入表格，我需要它询问每一次传球是否用户想要继续，如果是，那么它再次进行，如果不是那么它退出while循环。 如果用户没有输入至少4-8个数据，那么它会产生错误而不是打印出时间。 我相信错误是由于它第一次通过while循环后，它在for循环中执行8之前不再执行另一次传递。 我该如何解决这个问题。 请解释您的代码，并将其与我给出的上下文联系起来。
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 | import time datasets= [] carry_on = True while carry_on == True: for i in range(0, 8): print("Inputting Data for Lane", i) gender = str(input("Is the athlete male or female")) athlete = str(input("What is the athletes name")) finishTime = float(input("What was the finishing time")) dataset = [gender, athlete, finishTime] datasets.append(dataset) decision = input("Would you like to add another lane") if decision =="yes": carry_on = True else: carry_on = False print("") if 3 < i > 9: print("{0:<10}{1:<10}{2:<15}".format("Gender","Athlete","Finish time")) ds = sorted(datasets, key=lambda x:x[2], reverse=False) for s in ds: time.sleep(1) print("{0:<10}{1:<10}{2:<15}".format(s[0], s[1], s[2])) else: print("You have not chosen enough lanes, please choose atleast 4") |
首先，学习基础知识
尝试打破for循环
不确定是否需要
1 2 3 4 5 6 7 8 9 10 | for i in range(0, 8): print("Inputting Data for Lane", i) gender = str(input("Is the athlete male or female")) athlete = str(input("What is the athletes name")) finishTime = float(input("What was the finishing time")) dataset = [gender, athlete, finishTime] datasets.append(dataset) decision = input("Would you like to add another lane") if decision !="yes": break |
//按照你的代码和你提出的要求
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 | import time datasets= [] carry_on = True while carry_on == True: for i in range(0, 8): print("Inputting Data for Lane", i) gender = str(input("Is the athlete male or female")) athlete = str(input("What is the athletes name")) finishTime = float(input("What was the finishing time")) dataset = [gender, athlete, finishTime] datasets.append(dataset) decision = input("Would you like to add another lane") if decision =="yes": carry_on = True else: carry_on = False break print("") if 3 < i > 9: print("{0:<10}{1:<10}{2:<15}".format("Gender","Athlete","Finish time")) ds = sorted(datasets, key=lambda x:x[2], reverse=False) for s in ds: time.sleep(1) print("{0:<10}{1:<10}{2:<15}".format(s[0], s[1], s[2])) else: print("You have not chosen enough lanes, please choose atleast 4") |
你只能使用一个for循环和break指令：
1 2 3 4 5 6 7 8 9 10 | for i in range(8): print("Inputting Data for Lane", i) gender = input("Is the athlete male or female") athlete = input("What is the athletes name") finishTime = float(input("What was the finishing time")) dataset = [gender, athlete, finishTime] datasets.append(dataset) decision = input("Would you like to add another lane") if decision !="yes": break |
注意可以写入范围(0,8)：范围(8)
并且输入返回一个字符串，因此str(input(...))是无用的。
此外：
1 | if 3 < i > 9 |
手段：
1 | if i > 3 and i > 9: |
我想你的意思是：
1 | if 3 < i < 9: |
最后：如果用户输入的不是数字，float(input(...))可能会引发ValueError异常。 你应该添加一个try：except：construct。
for循环无论如何都会进行8次迭代，因此您将始终输入8个通道。
您可以完全删除for循环，并用一个简单的计数器替换它。
当用户选择添加另一个通道时，增加计数器，当它达到8时 - 结束循环。
像(在伪代码中)的东西：
1 2 3 4 5 6 7 8 9 10 11 | counter =0 while carry_on <read user input> if counter < 8 if decision =="yes" counter++ carry_on = true else carry_on = false <handle input here> |