Finding string index in .txt file
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 | import crypt import os import shutil '''curDir = os.getcwd() print(curDir) os.mkdir('NixFiles')''' '''shutil.move("/Users/Ayounes/Desktop/Python_dev/dictionary.txt", "/Users/Ayounes/Desktop/Python_dev/") shutil.move("/Users/Ayounes/Desktop/Python_dev/passwords.txt","/Users/Ayounes/Desktop/Python_dev/")''' def testPass(cryptPass): salt=cryptPass[0:2] dictFile = open('dictionary.txt', 'r') for word in dictFile.read().split(): #print(word) cryptWord = crypt.crypt(word, salt) #print(cryptWord) if(cryptWord == cryptPass): print('Found password: %s' % word) print('Index located at position: %d' % word.index("")) return print('Password was not found. ') return def main(): passFile = open('passwords.txt','r') cryptPass1 = passFile.readline() testPass(cryptPass1) if __name__ == '__main__': main() |
我的程序从passwords.txt文件中检索哈希。然后,它继续获取salt参数(哈希的前2个字符)并逐行散列dictionary.txt文件中的单词,同时将该哈希与passwords.txt文件中的原始哈希进行比较。
一旦我们有了匹配,它就假定打印出哪个密码是原始散列的解密匹配。
'graildcheese22'是dictionary.txt文件中位置3的第4个单词,它在位置0处不断输出索引。
如何在.txt文件中输出正确的位置?
原始哈希:22cwixwlb7twm
dictionary.txt中的解密哈希:"grilledcheese22"
迭代文件时使用Enumerate。
1 2 3 4 5 6 | for i, word in enumerate(dictFile.read().split()): ... ... print('Index located at position: %d' % i) #print('Index located at position: {}'.format(i)) #print(f'Index located at position: {i}') |