关于fizzbuzz：当我遵循Ruby rubocop样式指南并使用.zero时，方法失败了？而不是== 0

Method fail when I follow Ruby rubocop style guide and use .zero? instead of == 0

TODO：返回一系列整数，'Fizz'，'Buzz'或'FizzBuzz'
编写一个方法fizz_buzz，它以number作为参数，并且
将一个number元素的数组从1返回到number，但替换了一些
根据这些规则：

如果该数字可被3整除，则将其替换为'Fizz'
如果该数字可被5整除，则将其替换为'Buzz'
如果该数字可被3和5整除，则将其替换为'FizzBuzz'

如果我按照rubocop的样式指南使用.zero而不是== 0？我的方法失败了，我不明白为什么

我的样式编辑解决方案现在失败了

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def fizz_buzz(number)
fail ArgumentError,"#{number} is less than 1" if number < 1
a = [number]
while number > 1
number = number - 1
a.unshift(number)
a.map! { |x| (x % 15).zero? ? 'FizzBuzz' : x }
a.map! { |x| (x % 3).zero? ? 'Fizz' : x }
a.map! { |x| (x % 5).zero? ? 'Buzz' : x }
end
a
end

should return the array [ 1, 2, 'Fizz' ] for number 3 (FAILED - 1)
should return the array [ 1, 2, 'Fizz', 4, 'Buzz', 'Fizz', 7 ] for number 7 (FAILED - 2)
should return an array with 'FizzBuzz' at the 15th element of the array (15 is divisible by both 3 and 5) (FAILED - 3)

失败：

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1) fizz_buzz should return the array [ 1, 2, 'Fizz' ] for number 3
Failure/Error: a.map! { |x| (x % 5).zero? ? 'Buzz' : x }

NoMethodError:
undefined method `zero?' for"Fizz":String
# ./lib/fizz_buzz.rb:12:in `block in fizz_buzz'
# ./lib/fizz_buzz.rb:12:in `map!'
# ./lib/fizz_buzz.rb:12:in `fizz_buzz'
# ./spec/fizz_buzz_spec.rb:13:in `block (2 levels) in <top (required)>'

2) fizz_buzz should return the array [ 1, 2, 'Fizz', 4, 'Buzz', 'Fizz', 7 ] for number 7
Failure/Error: a.map! { |x| (x % 5).zero? ? 'Buzz' : x }

NoMethodError:
undefined method `zero?' for"Fizz":String
# ./lib/fizz_buzz.rb:12:in `block in fizz_buzz'
# ./lib/fizz_buzz.rb:12:in `map!'
# ./lib/fizz_buzz.rb:12:in `fizz_buzz'
# ./spec/fizz_buzz_spec.rb:17:in `block (2 levels) in <top (required)>'

3) fizz_buzz should return an array with 'FizzBuzz' at the 15th element of the array (15 is divisible by both 3 and 5)
Failure/Error: a.map! { |x| (x % 5).zero? ? 'Buzz' : x }

NoMethodError:
undefined method `zero?' for"Fizz":String
# ./lib/fizz_buzz.rb:12:in `block in fizz_buzz'
# ./lib/fizz_buzz.rb:12:in `map!'
# ./lib/fizz_buzz.rb:12:in `fizz_buzz'
# ./spec/fizz_buzz_spec.rb:21:in `block (2 levels) in <top (required)>'

我的工作方案风格失败了

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def fizz_buzz(number)
fail ArgumentError,"#{number} is less than 1" if number < 1
a = [number]
while number > 1
number = number - 1
a.unshift(number)
a.map! { |x| (x % 15) == 0 ? 'FizzBuzz' : x }
a.map! { |x| (x % 3) == 0 ? 'Fizz' : x }
a.map! { |x| (x % 5) == 0 ? 'Buzz' : x }
end
a
end

鉴于解决方案

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# def fizz_buzz(number)
# fail ArgumentError,"#{number} should be greater than 1" if number < 1
# (1..number).map do |i|
# if (i % 3).zero? && (i % 5).zero?
# 'FizzBuzz'
# elsif (i % 3).zero?
# 'Fizz'
# elsif (i % 5).zero?
# 'Buzz'
# else
# i
# end
# end
# end