如何在c＃中获取不同的字符

How to get distinct characters in c#

我有个密码

1	String code="AABBDDCCRRFF";

在这段代码中，我只想检索不同的字符

输出应类似于：

1	ANS: ABDCRF

1 2	string code ="AABBDDCCRRFF"; string answer = new String(code.Distinct().ToArray());

相关讨论

使用Dotnet2.0兼容代码的可选选项：

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public string RemoveDuplicateChars(string input)
{
var stringBuilder = new StringBuilder(input);

foreach (char c in input)
{
stringBuilder.Replace(c.ToString(), string.Empty)
.Append(c.ToString());
}

return stringBuilder.ToString();
}

这是一种提供字符串和不同字符计数的方法…

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using System;
using System.Collections.Generic;

namespace StringDict
{
class Program
{
static IDictionary<char, int> charDict =new Dictionary<char, int>();
static private string _charStr ="s;ldfjgsl;dkkjfg;lsdkfjg;lsdkfjg;lsdkfjg;lsdkfj";
private static int _outInt=0;
static void Main(string[] args)
{
foreach (var ch in _charStr)
{
if (!charDict.TryGetValue(ch,out _outInt))
{
charDict.Add(new KeyValuePair<char, int>(ch,1));
}
else
{
charDict[ch]++;
}
}
Console.Write("Unique Characters:");
Console.WriteLine('
');
foreach (var kvp in charDict)
{
Console.Write(kvp.Key);
}
Console.WriteLine('
');
foreach (var kvp in charDict)
{
Console.WriteLine("Char:"+kvp.Key+" Count:"+kvp.Value);
}
Console.ReadLine();
}
}
}

输出…

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Unique Characters:

s;ldfjgk

Char: s Count: 6
Char: ; Count: 6
Char: l Count: 6
Char: d Count: 6
Char: f Count: 6
Char: j Count: 6
Char: g Count: 5
Char: k Count: 6

你可以这样做

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var s ="AABBDDCCRRFF";
var result = s.Distinct();
var distinct = result.Aggregate(string.Empty, (current, c) => current + c.ToString());
Console.WriteLine(distinct);

在林肯怎么样？

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var str ="AABBCCDDDDDDEEEEEFFF";
var unique = str.ToCharArray().Distinct();
Console.WriteLine("Answer: {0}.", string.Join(string.Empty, unique));

就为了它-使用一个StringBuilder

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string code ="AABBDDCCRRFF";
StringBuilder sb = new StringBuilder();
code.Distinct().ToList().ForEach(c => sb.Append(c));
MessageBox.Show(sb.ToString());