How to log source file name and line number in Python
是否可以装饰/扩展python标准日志记录系统，以便在调用日志记录方法时，它还会记录文件和调用它的行号，或者调用它的方法？
当然，检查记录文档中的格式化程序。 特别是lineno和pathname变量。
%(pathname)s Full pathname of the source file where the logging call was issued(if available).
%(filename)s Filename portion of pathname.
%(module)s Module (name portion of filename).
%(funcName)s Name of function containing the logging call.
%(lineno)d Source line number where the logging call was issued (if available).
看起来像这样：
1 | formatter = logging.Formatter('[%(asctime)s] p%(process)s {%(pathname)s:%(lineno)d} %(levelname)s - %(message)s','%m-%d %H:%M:%S') |
除了Seb非常有用的答案之外，这里还有一个方便的代码片段，它以合理的格式演示了记录器的使用情况：
1 2 3 4 5 6 7 8 9 10 11 12 | #!/usr/bin/env python import logging logging.basicConfig(format='%(asctime)s,%(msecs)d %(levelname)-8s [%(filename)s:%(lineno)d] %(message)s', datefmt='%Y-%m-%d:%H:%M:%S', level=logging.DEBUG) logger = logging.getLogger(__name__) logger.debug("This is a debug log") logger.info("This is an info log") logger.critical("This is critical") logger.error("An error occurred") |
生成此输出：
1 2 3 4 | 2017-06-06:17:07:02,158 DEBUG [log.py:11] This is a debug log 2017-06-06:17:07:02,158 INFO [log.py:12] This is an info log 2017-06-06:17:07:02,158 CRITICAL [log.py:13] This is critical 2017-06-06:17:07:02,158 ERROR [log.py:14] An error occurred |
要以将调试日志记录发送到标准输出的方式构建上述内容：
1 2 3 4 5 6 7 8 9 10 11 12 13 14 | import logging import sys root = logging.getLogger() root.setLevel(logging.DEBUG) ch = logging.StreamHandler(sys.stdout) ch.setLevel(logging.DEBUG) FORMAT ="[%(filename)s:%(lineno)s - %(funcName)20s() ] %(message)s" formatter = logging.Formatter(FORMAT) ch.setFormatter(formatter) root.addHandler(ch) logging.debug("I am sent to standard out.") |
将上述内容放入名为
1 | [debug_logging_example.py:14 - <module>() ] I am sent to standard out. |
然后，如果要关闭记录注释
对于单个文件(例如类分配)，我发现这是一种更好的方法，而不是使用