关于python：定义一个使用函数内部列表范围的函数


Defining a function that uses range of a list inside the function

我在运行此命令时(在第1行)收到一个错误，我不知道如何修复它。我想让一个函数遍历列表中的所有状态，如果找到了，通知用户。谢谢！

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def find_state(in range(0,len(stateslist)))
    stateslist = [AL, AK, AZ, AR, CA, CO, CT]
    if state == stateslist
    return:"Yes, this state is in the US."

state = input("Input the state ID you are checking. (I.E. CO)")

print(find_state)
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您正在编写的不是真正的Python，您应该了解语言的基本方面，例如编写字符串、函数和循环。

此外，在编写可能成为int/float变量的数字或以小写形式编写文本时，应该始终考虑用户的问题。

所以这是最好的解决方案：

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def find_state(state):
    stateslist = ["AL","AK","AZ","AR","CA","CO","CT"]
    if state.upper() in stateslist:
        return"Yes, this state is in the {}.".format(state.upper())
    return"State not found"

state = find_state(input("Input the state ID you are checking. (I.E. CO)"))
print(state)
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stateslist = ['AL', 'AK', 'AZ', 'AR', 'CA', 'CO', 'CT']

state = input("Input the state ID you are checking. (I.E. CO)")

if state in stateslist:
  print('Great, it is in!')
else:
  print('No, no such state')

函数形式：

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def test_state(state):
  return state in ['AL', 'AK', 'AZ', 'AR', 'CA', 'CO', 'CT']

state = input("Input the state ID you are checking. (I.E. CO)")

if test_state(state):
  print('Great, it is in!')
else:
  print('No, no such state')
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